An urn contains 10 black and 5 white balls. Two balls are drawn

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821.

Prove that if E and F are independent events,  then so are the events E and F'.

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823.

Two events A and B will be independent, if

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824. An urn contains 10 black and 5 white balls. Two balls are drawn from the urn one after the other without replacement. What is the probability that both drawn balls are black?


Number of black balls = 10
Number of white balls = 5
∴ total number of balls = 10 + 5 = 15
Let E and F denote respectively the events that first and second ball drawn are black.
      Now P(E) = P(black ball in first draw) = 10 over 15
Since there is no replacement
 therefore space space space straight P left parenthesis straight E vertical line straight F right parenthesis space equals space 9 over 14
By multiplication rule of probability,
                     straight P left parenthesis straight E intersection straight F right parenthesis space equals space straight P left parenthesis straight E right parenthesis space straight P left parenthesis straight F vertical line straight E right parenthesis space equals space 10 over 15 cross times 9 over 14 space equals 3 over 7

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