Find the angle between the following pair of lines: from Mathem
    • Zigya Logo

    Previous Year Papers

    Download Solved Question Papers Free for Offline Practice and view Solutions Online.

    Test Series

    Take Zigya Full and Sectional Test Series. Time it out for real assessment and get your results instantly.

    Test Yourself

    Practice and master your preparation for a specific topic or chapter. Check you scores at the end of the test.
    Advertisement

    Three Dimensional Geometry

    Multiple Choice QuestionsShort Answer Type

    71. Find the angle between the lines whose direction ratios are a, b, c and b – c, c – a, a – b.
    74 Views
    Answer
    72. Find the angle between each of the following pairs of lines:
    fraction numerator straight x minus 2 over denominator 3 end fraction space equals space fraction numerator straight y plus 1 over denominator negative 2 end fraction comma space space straight z space equals space 2 comma space space space fraction numerator straight x minus 1 over denominator 1 end fraction space equals space fraction numerator 2 straight y plus 3 over denominator 3 end fraction space equals space fraction numerator straight z plus 5 over denominator 2 end fraction
    84 Views
    Answer
    73. Find the angle between pair of lines:
                       fraction numerator straight x plus 3 over denominator 3 end fraction space equals space fraction numerator straight y minus 1 over denominator 5 end fraction space equals space fraction numerator straight z plus 3 over denominator 4 end fraction

    and          fraction numerator straight x plus 1 over denominator 1 end fraction space equals space fraction numerator straight y minus 4 over denominator 1 end fraction space equals space fraction numerator straight z minus 5 over denominator 2 end fraction
    79 Views
    Answer
    Advertisement
    Zigya App

    74. Find the angle between the following pair of lines:
    fraction numerator straight x minus 2 over denominator 2 end fraction space equals space fraction numerator straight y minus 1 over denominator 5 end fraction space equals fraction numerator straight z plus 3 over denominator negative 3 end fraction space space and space space fraction numerator straight x plus 1 over denominator negative 1 end fraction space equals space fraction numerator straight y minus 4 over denominator 8 end fraction space equals space fraction numerator straight z minus 5 over denominator 4 end fraction

    The equations of lines are
                     fraction numerator straight x minus 2 over denominator 2 end fraction space equals space fraction numerator straight y minus 1 over denominator 5 end fraction space equals space fraction numerator straight z plus 3 over denominator negative 3 end fraction

    and            fraction numerator straight x plus 1 over denominator negative 1 end fraction space equals space fraction numerator straight y minus 4 over denominator 8 end fraction space equals space fraction numerator straight z minus 5 over denominator 4 end fraction
    Direction ratios of two lines are 2, 5, -3 and – 1, 8, 4.
    Let θ be the angle between the lines.
    therefore space space space cos space straight theta space equals space fraction numerator left parenthesis 2 right parenthesis thin space left parenthesis negative 1 right parenthesis space plus space left parenthesis 5 right parenthesis thin space left parenthesis 8 right parenthesis space plus space left parenthesis negative 3 right parenthesis thin space left parenthesis 4 right parenthesis over denominator square root of 4 plus 25 plus 9 end root space square root of 1 plus 64 plus 16 end root end fraction space equals space fraction numerator negative 2 plus 40 minus 12 over denominator square root of 38 space square root of 81 end fraction space space space space space space space space space space space space space space space space space equals fraction numerator 26 over denominator 9 square root of 38 end fraction therefore space space space space space space space space space space straight theta space equals space cos to the power of negative 1 end exponent space open parentheses fraction numerator 26 over denominator 9 square root of 38 end fraction close parentheses space
    95 Views
  • Switch Icon Switch
    • Advertisement
    Advertisement
    75. Find the angle between the following pair of lines:
    fraction numerator 5 minus straight x over denominator 3 end fraction space equals space fraction numerator straight y plus 3 over denominator negative 2 end fraction comma space space straight z space equals space 5 space space space and space space straight x over 1 space equals space fraction numerator 1 minus straight y over denominator 3 end fraction space equals fraction numerator straight z minus 5 over denominator 2 end fraction
    77 Views
    Answer
    76. Find the angle between the following pair of lines:
     straight x over 2 space equals space straight y over 2 space equals space straight z over 1 space space and space space fraction numerator straight x minus 5 over denominator 4 end fraction space equals space fraction numerator straight y minus 2 over denominator 1 end fraction space equals space fraction numerator straight z minus 3 over denominator 8 end fraction
    87 Views
    Answer
    77. Find the angle between the following pair of lines:
    fraction numerator straight x minus 5 over denominator 1 end fraction equals space fraction numerator 2 straight y plus 6 over denominator negative 2 end fraction space equals space fraction numerator straight z minus 3 over denominator 1 end fraction space space and space fraction numerator straight x minus 2 over denominator 3 end fraction space equals space fraction numerator straight y plus 1 over denominator 4 end fraction space equals space fraction numerator straight z minus 6 over denominator 5 end fraction
     
    84 Views
    Answer
    78. Find the angle between the lines
    straight x over 1 space equals fraction numerator negative straight y over denominator 0 end fraction space equals space fraction numerator straight z over denominator negative 1 end fraction space space and space space straight x over 3 space equals space straight y over 4 space equals straight z over 5
    81 Views
    Answer
    Advertisement

    Multiple Choice QuestionsLong Answer Type

    79. Find the value of p so that the lines
    fraction numerator 1 minus straight x over denominator 3 end fraction space equals space fraction numerator 7 straight y minus 14 over denominator 2 space straight p end fraction space equals space fraction numerator straight z minus 3 over denominator 2 end fraction space space and space space fraction numerator 7 minus 7 straight z over denominator 3 space straight p end fraction space equals space fraction numerator straight y minus 5 over denominator 1 end fraction space equals space fraction numerator 6 minus straight z over denominator 5 end fraction
    80 Views
    Answer

    Multiple Choice QuestionsShort Answer Type

    80. Show that the lines
    fraction numerator straight x minus 5 over denominator 7 end fraction space equals space fraction numerator straight y plus 2 over denominator negative 5 end fraction space equals straight z over 1 space and space straight x over 1 space equals space straight y over 2 space equals space straight z over 3 are prependicular to each other. 
    85 Views
    Answer
    Advertisement
    Flag Popup Icon
    Flag it
    Submit
    Flag Popup Icon
    Switch to
    flexipad
    Share It Icon
    Share it
    Share It
    Share it