Find the equations of the planes that passes through three point

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 Multiple Choice QuestionsShort Answer Type

211. Find the equation of the plane through the points (0, – 1, 0), (2, 1, –1) and (1,1,1). 
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212. Find the equation of the plane passing through the points (0. – 1, 0), (1, 1, 1) and (3, 3,0).
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 Multiple Choice QuestionsLong Answer Type

213. Find the equation of the plane through the three points (1, 1, 1), (1, – 1, 1) and (–7, – 3,–5).
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 Multiple Choice QuestionsShort Answer Type

214.

Find the vector equation of the plane passing through the point A(2, 2, –1), B(3, 4, 2) and C (7, 0, 6). Also find the cartesian equation of the plane.

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215. Find the vector equations of the plane passing through the points R(2, 5, –3), S(– 2, – 3, 5) and T(5, 3, – 3).
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216. Find the equations of the planes that passes through three points:
(1, 1,–1), (6, 4, –5),(–4, –2, 3)


The equation of line through (1, 1, –1), (6, 4, – 5) is
            fraction numerator straight x minus 1 over denominator 6 minus 1 end fraction space equals space fraction numerator straight y minus 1 over denominator 4 minus 1 end fraction space equals space fraction numerator straight z plus 1 over denominator negative 5 plus 1 end fraction

or            fraction numerator straight x minus 1 over denominator 5 end fraction space equals space fraction numerator straight y minus 1 over denominator 3 end fraction space equals space fraction numerator straight z plus 1 over denominator negative 4 end fraction
The point (– 4, –2, 3) will lie on this line
if  fraction numerator negative 4 minus 1 over denominator 5 end fraction space equals space fraction numerator negative 2 minus 1 over denominator 3 end fraction space equals space fraction numerator 3 plus 1 over denominator negative 4 end fraction
i.e. if –1 = –1 = –1, which is true
∴ given points (1, 1, –1), (6, 4, – 5), (– 4, – 2, 3) are collinear.
∴ infinite number of planes pass through the given points.
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217. Find the equations of the planes that passes through three points:
(1, 1, 0),  (1, 2, 1), (–2, 2, –1)
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 Multiple Choice QuestionsLong Answer Type

218. If from a point P (a, b, c) perpendiculars PA and PB are drawn to yz and zx-planes, then find the vector equation of the plane OAB.
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219. Find the equation of plane through the points (2, 2, 1), (9, 3, 6), and perpendicular to the plane 2x + 6y + 6z = 9.
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220. Find the equation of the plane through the points (2, 2, 1), (9, 3, 6) and perpendicular to the plane 2x + 6y + 6z – 1 = 0. 
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