Short Answer Type
meets the plane x + y + z = 2.
The equation of given plane is
x – y + z = 5 ...(1)
The equation of the line through P (1,–2, 3) parallel to the line 
are 
Any point on it is Q (2 r + 1, 3 r –2, – 6 r + 3)
Let it lie on plane (1)
∴ 2r + 1 – 3r + 2 – 6r + 3 = 5
measured parallel to the plane 4 x + 12 y - 3z + 1 = 0.
Long Answer Type
Short Answer Type
and the point of intersection of the line 
with the plane x – y + z = 5.
Find the distance of the point (2, 3, 4) from the plane 3x + 2y + 2z + 5 = 0, measured parallel to the line 
Long Answer TypeShort Answer Type
Switch
intersect.
