The equation of the plane which is equidistant from the two parallel planes 2x - 2y + z + 3= 0 and 4x - 4y + 2z + 9 = 0 is
8x - 8y + 4z + 15 = 0
8x - 8y + 4z - 15 = 0
8x - 8y + 4z + 3 = 0
8x - 8y + 4z - 3 = 0
The vector equation of the plane through the point (2, 1, - 1) and parallel to the plane r - (i + 3j - k) = 0 is
r . (i + 9j + 11k) = 6
r . (i - 9j + 11k) = 4
r . (i + 3j - k) = 6
r . (i + 3j - k) = 4
If the foot of the perpendicular drawn from the point (5, 1, - 3) to a plane is (1, - 1, 3), then the equation of the plane is
2x + y - 3z + 8 = 0
2x + y + 3z + 8 = 0
2x - y - 3z + 8 = 0
2x - y + 3z + 8 = 0
The equation of the plane through the line of intersection of the planes x - y + z + 3 = 0 and x + y + 22 + 1 = 0 and parallel to x-axis is
2y - z = 2
2y + z = 2
4y + z = 4
y - 2z = 3
If 3p + 2q = i + j + k and 3p - 2q = i - j - k, then the angle between p and q is
D.
Given, 3p + 2q = i + j + k ...(i)
and 3p - 2q = i - j - k ...(ii)
On adding Eqs. (i) and (ii), we get
6p = 2i
On subtracting Eq. (ii) from Eq. (i), we get
4q = 2(j + k)
Let be the angle between p and q, then
The point of intersection of the straight line with the plane x + 3y - z + 1 = 0 is
(3, - 1, 1)
(- 5, 1, - 1)
(2, 0, 3)
(4, - 2, - 1)
The point P(x, y, z) lies in the first octant and its distance from the origin is 12 units. If the position vector of P make 45° and 60° with the x-axis and y-axis respectively, then the coordinates of P are
The distance between the planes r . (i + 2j - 2k) + 5 = 0 and r . (2i + 4j - 4k) - 16 = 0 is
3
13