Important Questions of Trigonometric Functions Mathematics | Zigya

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621.

AB is a vertical pole with B at the ground level and A at the top. A man finds that the angle of elevation of the point A from a certain point C on the ground is 60°. He moves away from the pole along the line BC to a point D such that CD = 7 m. From D the angle of elevation of the point A is 45°.
Then the height of the pole is

  • fraction numerator 7 square root of 3 over denominator 2 end fraction. fraction numerator 1 over denominator square root of 3 begin display style minus end style begin display style 1 end style end fraction straight m
  • fraction numerator 7 square root of 3 over denominator 2 end fraction. left parenthesis square root of 3 plus 1 right parenthesis space straight m
  • fraction numerator 7 square root of 3 over denominator 2 end fraction. left parenthesis square root of 3 minus 1 right parenthesis space straight m
  • fraction numerator 7 square root of 3 over denominator 2 end fraction. left parenthesis square root of 3 minus 1 right parenthesis space straight m
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622.

The value of cot open parentheses cosec to the power of negative 1 end exponent space 5 over 3 space plus space tan to the power of negative 1 end exponent 2 over 3 close parentheses space is

  • 6/17

  • 5/17

  • 4/17

  • 4/17

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623. If space sin to the power of negative 1 end exponent space open parentheses straight x over 5 close parentheses space plus space cosec to the power of negative 1 end exponent space open parentheses 5 over 4 close parentheses space equals space straight pi over 2 then the value of x
  • 1

  • 3

  • 4

  • 4

104 Views

624.

A tower stands at the centre of a circular park. A and B are two points on the boundary of the park such that AB (= a) subtends an angle of 60º at the foot of the tower, and the angle of elevation of the top of the tower from A or B is 30º. The height of the tower is

  • 2 straight a divided by square root of 3
  • 2 straight a square root of 3
  • straight a divided by square root of 3
  • straight a divided by square root of 3
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625.

The value of sum from straight k equals 1 to 10 of space open parentheses sin space fraction numerator 2 kπ over denominator 11 end fraction plus space straight i space cos space fraction numerator 2 kπ over denominator 11 end fraction close parentheses space is

  • i

  • 1

  • -i

  • -i

131 Views

626.

If 0 < x < π and cosx + sinx = 1/2 , then tanx is

  • fraction numerator left parenthesis 1 minus square root of 7 right parenthesis over denominator 4 end fraction
  • fraction numerator left parenthesis 4 minus square root of 7 right parenthesis over denominator 3 end fraction
  • negative fraction numerator left parenthesis 4 minus square root of 7 right parenthesis over denominator 3 end fraction
  • negative fraction numerator left parenthesis 4 minus square root of 7 right parenthesis over denominator 3 end fraction
144 Views

627. limit as straight n rightwards arrow infinity of space open square brackets 1 over straight n squared sec squared space 1 over straight n squared plus 2 over straight n squared space plus 2 over straight n squared sec squared 4 over straight n squared plus.....1 over straight n squared sec squared 1 close square brackets equal
  • 1 half sec space 1
  • 1 half cosec space 1
  • tan 1

  • tan 1

107 Views

628.

In a triangle PQR, ∠R =π/2. If (P/2) and tan (Q/2) are the roots of ax2 +bx+ c = 0, a ≠ 0 then 

  • a = b + c

  • c = a + b

  • b = c

  • b = c

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629.

In a triangle, ABC, let ∠C = π/2 . If r is the in radius and R is the circumradius of the triangle ABC, then 2 (r + R) equals

  • b + c

  • a+b

  • a + b + c

  • a + b + c

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630. If space straight l subscript 1 space equals space integral subscript 0 superscript 1 space 2 to the power of straight x squared 1 end exponent space dx comma space straight I subscript 2 space equals space integral subscript 0 superscript 1 space 2 to the power of straight x cubed end exponent space dx space comma space straight I subscript 3 space equals space integral subscript 1 superscript 2 space 2 to the power of straight x squared space end exponent dx space and space straight I subscript 4 space equals space integral subscript 1 superscript 2 2 to the power of straight x cubed space end exponent space dx space then
  • I2 > I1

  • I1 > I2

  • I3 = I4

  • I3 = I4

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