If  find the value of: from Mathematics Trigonometric Functio

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 Multiple Choice QuestionsShort Answer Type

81.

If tan left parenthesis straight alpha plus straight theta right parenthesis space equals space straight n space tan left parenthesis straight alpha minus straight theta right parenthesis comma show that left parenthesis straight n plus 1 right parenthesis space sin 2 straight theta space equals space left parenthesis straight n minus 1 right parenthesis space sin 2 straight alpha

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82.

Find the maximum and minimum values of:

straight a space cosx plus straight b space sinx

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83.

Find the maximum and minimum values of:


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84.

Find the maximum and minimum values of:

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85.

Prove the following:

cos 4 straight x space equals space 1 minus 8 sin squared straight x space cos squared straight x

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86.

Prove the following:

tan 4 straight x space equals space fraction numerator 4 tanx space left parenthesis 1 minus tan squared straight x right parenthesis over denominator 1 minus 6 tan squared straight x plus tan to the power of 4 straight x end fraction




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87.

Prove that:

fraction numerator sin 2 straight x over denominator 1 plus cos 2 straight x end fraction space equals space tanx

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88.

Prove that:

fraction numerator 1 plus sin 2 straight x minus cos 2 straight x over denominator 1 plus sin 2 straight x plus cos 2 straight x end fraction space equals space tanx

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89.

If tan open parentheses straight x over 2 close parentheses space equals space 3 over 4 comma find the value of:

sin space straight x


We know that

          sin space 2 straight A space equals space fraction numerator 2 space tanA over denominator 1 plus tan squared straight A end fraction

Replacing A byspace space straight x over 2 comma we get

                          sinx space equals space fraction numerator 2 tan open parentheses begin display style straight x over 2 end style close parentheses over denominator 1 plus tan squared open parentheses begin display style straight x over 2 end style close parentheses end fraction space equals space fraction numerator 2 open parentheses begin display style 3 over 4 end style close parentheses over denominator 1 plus open parentheses begin display style 3 over 4 end style close parentheses squared end fraction space equals space 3 over 2 cross times 16 over 25 equals space 24 over 25

Hence,                 sinx space equals space 24 over 25

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90.

If tan open parentheses straight x over 2 close parentheses space equals space 3 over 4 comma find the value of:

space space cos space straight x

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