Find  in the following: is in quadrant III from Mathematics

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 Multiple Choice QuestionsShort Answer Type

101.

Find the value of:

cos straight pi over 8




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 Multiple Choice QuestionsLong Answer Type

102.

Prove that:

tan space straight A space plus space tan space left parenthesis 60 degree plus straight A right parenthesis minus tan space left parenthesis 60 degree minus straight A right parenthesis space equals space 3 space tan space 3 straight A.

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 Multiple Choice QuestionsShort Answer Type

103.

Show that:

cos straight pi over 7. space cos fraction numerator 2 straight pi over denominator 7 end fraction. space cos fraction numerator 4 straight pi over denominator 7 end fraction space equals space minus 1 over 8

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 Multiple Choice QuestionsLong Answer Type

104.

Find <pre>uncaught exception: <b>mkdir(): Permission denied (errno: 2) in /home/config_admin/public/felixventures.in/public/application/css/plugins/tiny_mce_wiris/integration/lib/com/wiris/util/sys/Store.class.php at line #56mkdir(): Permission denied</b><br /><br />in file: /home/config_admin/public/felixventures.in/public/application/css/plugins/tiny_mce_wiris/integration/lib/com/wiris/util/sys/Store.class.php line 56<br />#0 [internal function]: _hx_error_handler(2, 'mkdir(): Permis...', '/home/config_ad...', 56, Array)
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#6 {main}</pre> in the following:

tanx space equals space minus 4 over 3 comma space straight x space is space in space quadrant space II

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105.

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#6 {main}</pre> in the following:

cosx space equals space minus 1 third comma space straight x is in quadrant III


cosx space equals space minus 1 third  (Given) x lies in quadrant III

rightwards double arrow                   straight pi less than straight x less than fraction numerator 3 straight pi over denominator 2 end fraction   rightwards double arrow       straight pi over 2 less than straight x over 2 less than fraction numerator 3 straight pi over denominator 4 end fraction

∴  straight x over 2 lies in quadrant II.

therefore space space cos straight x over 2 space and space tan straight x over 2 are -ve, but sin straight x over 2 is +ve

Now,             cos open parentheses straight x over 2 close parentheses space equals space minus square root of fraction numerator 1 plus cosx over denominator 2 end fraction end root space equals space minus square root of fraction numerator 1 minus begin display style 1 third end style over denominator 2 end fraction end root space rightwards double arrow space space   cos open parentheses straight x over 2 close parentheses space equals space minus square root of 1 third end root

                    sin open parentheses straight x over 2 close parentheses space equals space plus square root of fraction numerator 1 minus cosx over denominator 2 end fraction end root space equals space square root of fraction numerator 1 plus begin display style 1 third end style over denominator 2 end fraction end root    rightwards double arrow   sin open parentheses straight x over 2 close parentheses space equals space square root of 2 over 3 end root

                   tan open parentheses straight x over 2 close parentheses space equals space fraction numerator sin open parentheses begin display style straight x over 2 end style close parentheses over denominator cos open parentheses begin display style straight x over 2 end style close parentheses end fraction space equals space fraction numerator square root of begin display style 2 over 3 end style end root over denominator negative square root of begin display style 1 third end style end root end fraction             rightwards double arrow    tan open parentheses straight x over 2 close parentheses space equals space minus square root of 2
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 Multiple Choice QuestionsShort Answer Type

106.

If cosx space equals space 1 half open parentheses straight a plus 1 over straight a close parentheses comma show that:  cos 2 straight x space equals space 1 half open parentheses straight a squared plus 1 over straight a squared close parentheses

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107.

If cos x = 1 half open parentheses straight a plus 1 over straight a close parentheses comma show that:

cos 3 straight x space equals space 1 half open parentheses straight a cubed plus 1 over straight a cubed close parentheses


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108.

Prove the following:

fraction numerator sin 5 straight x plus sin 3 straight x over denominator cos 5 straight x plus cos 3 straight x end fraction space equals space tan 4 straight x

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109.

Prove the following:

fraction numerator sin space straight x minus sin space straight y over denominator cos space straight x plus cos space straight y end fraction space equals space tan open parentheses fraction numerator straight x minus straight y over denominator 2 end fraction close parentheses

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110.

Prove the following:

sin open parentheses fraction numerator 7 straight pi over denominator 12 end fraction close parentheses plus cos open parentheses fraction numerator 7 straight pi over denominator 12 end fraction close parentheses space equals space cos open parentheses straight pi over 4 close parentheses space equals fraction numerator 1 over denominator square root of 2 end fraction


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