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 Multiple Choice QuestionsMultiple Choice Questions

1.

Which among the following metals is employed to provide cathodic protection to iron?

  • Zinc

  • Nickel

  • Tin

  • Lead


2.

Galvanization is applying a coating of:

  • Cr

  • Cu

  • Zn

  • Zn

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3.

Two Faraday of electricity is passed through a solution of CuSO4. The mass of copper deposited at the cathode is: (at. mass of Cu = 63.5 amu)

  • 0 g

  • 63.5 g

  • 2 g

  • 2 g

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4.

The equivalent conductance of NaCl at concentration C at infinite dilution are λC and λ respectively. The correct relationship between λC and λ  is given as (where the constant B is positive)

  • λC = λ +(B)C

  • λC = λ -(B)C

  • λC = λ -(B)square root of straight C

  • λC = λ -(B)square root of straight C

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5.

Given below are the half-cell reactions
Mn2+ + 2e- → Mn; Eo = - 1.18 eV
2(Mn3+ + e- →Mn2+); Eo = +1.51 eV
The Eo for 3Mn2+ → Mn + 2Mn3+ will be

  • -2.69 V; the reaction will not occur

  • -2.69 V; the reaction will occure

  • -0.33 V; the reaction will not occur

  • -0.33 V; the reaction will not occur


A.

-2.69 V; the reaction will not occur

Standard element potential of reaction [ Eo] can be calculated as
Eocell = ER-EP
where ER = SRP of reactant
EP = SRP of product
If Eocell = +ve, then the reaction is spontaneous otherwise non-spontaneous.

therefore, For Mn2+ disproportionation
Eo = - 1.51 V - 1.18 V = - 2.69 V < 0

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6.

Given, 

straight E subscript Cr to the power of 3 plus end exponent divided by Cr end subscript superscript straight o space equals space minus space 0.74 space straight V semicolon
straight E subscript MnO subscript 4 superscript minus divided by Mn to the power of 2 plus end exponent end subscript superscript straight o space equals space 1.51 space straight V
straight E subscript Cr subscript 2 straight O subscript 7 superscript 2 minus end superscript divided by Cr to the power of 3 plus end exponent end subscript superscript straight o space equals space 1.33 space straight V semicolon
straight E subscript Cl divided by Cl to the power of negative 1 end exponent end subscript superscript straight o space equals space 1.36 space straight V
Based on the data given above, strongest oxidising agent will be

  • Cl

  • Cr3+

  • Mn2+

  • Mn2+

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7.

Four successive members of the first-row transition elements are listed below with atomic numbers. Which one of them is expected to have the highest straight E subscript straight M to the power of 3 plus end exponent divided by straight M to the power of 2 plus end exponent end subscript superscript straight o  value?

  • Cr (Z =24)

  • Mn(Z =25)

  • Fe (Z = 26)

  • Fe (Z = 26)

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8.

How many litres of water must be added to 1 L to an aqueous solution of HCl with a pH of 1 create an aqueous solution with PH of 2?

  • 0.1 L

  • 0.9 L 

  • 2.0 L 

  • 2.0 L 

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9.

The reduction potential of hydrogen half-cell will be negative if 

  • p(H2) = 1 atm and [H+] = 2.0 M

  • p(H2) = 1 atm and [H+] = 1.0 M

  • p(H2) = 2 atm and [H+] = 1.0 M

  • p(H2) = 2 atm and [H+] = 1.0 M

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10.

The degree of dissociation (α) of a weak electrolyte ,AxBy is related to van't Hoff factor (i) by the expression

  • straight alpha space equals space fraction numerator 1 minus 1 over denominator left parenthesis straight x plus straight y minus 1 right parenthesis end fraction
  • straight alpha space equals space fraction numerator 1 minus 1 over denominator left parenthesis straight x plus straight y plus 1 right parenthesis end fraction
  • straight alpha space equals space fraction numerator straight x plus straight y minus 1 over denominator straight i minus 1 end fraction
  • straight alpha space equals space fraction numerator straight x plus straight y minus 1 over denominator straight i minus 1 end fraction
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