Previous Year Papers

Download Solved Question Papers Free for Offline Practice and view Solutions Online.

Test Series

Take Zigya Full and Sectional Test Series. Time it out for real assessment and get your results instantly.

Test Yourself

Practice and master your preparation for a specific topic or chapter. Check you scores at the end of the test.
Advertisement

 Multiple Choice QuestionsMultiple Choice Questions

1.

The area (in sq. units) enclosed between the curves y = x2 and y = x is

  • 23

  • 16

  • 13

  • 1


2.

If one of the diameters of the circle, given by the equation, x2+y2−4x+6y−12=0, is a chord of a circle S, whose centre is at (−3, 2), then the radius of S is:

  • 5√2

  • 5√3

  • 5

  • 10

786 Views

3.

Let P be the point on the parabola, y2=8x which is at a minimum distance from the centre C of the circle, x2+(y+6)2=1. Then the equation of the circle, passing through C and having its centre at P is:

  • x2+y2−4x+8y+12=0

  • x2+y2−x+4y−12=0

  • x2+y2− 4 x +2y−24=0

  • x2+y2− 4 x +2y−24=0

358 Views

4.

The eccentricity of the hyperbola whose length of the latus rectum is equal to 8 and the length of its conjugate axis is equal to half of the distance between its foci, is:

  • 4/3

  • 4/√3

  • 2/√3

  • √3

264 Views

Advertisement
5.

The area (in sq units) of the region described by {x,y): y2 ≤ 2x and y ≥ 4x-1} is

  • 7/32

  • 5/64

  • 15/64

  • 15/64

284 Views

6.

The area (in sq units) of the quadrilateral formed by the tangents at the end points of the latera recta to the ellipsestraight x squared over 9 plus straight y squared over 5 space equals space 1 space is space

  • 27/4

  • 18

  • 27/2

  • 27/2

998 Views

7.

Let O be the vertex and Q be nay point on the parabola x2 = 8y. If the point P divides the line segment OQ internally in the ratio 1:3 then the locus of P is 

  • x2= y

  • y2 =x

  • y2 =2x

  • y2 =2x

349 Views

8.

If =-1 and x =2 are extreme points of f(x) =α log|x| + βx2 +x, then

  • α = -6, β = 1/2

  • α = -6, β = -1/2

  • α = 2, β = -1/2

  • α = 2, β = -1/2

307 Views

Advertisement
9.

The area of the region described by A = {(x,y): x2 +y2 ≤ 1 and y2 ≤1-x} is

  • straight pi over 2 plus 4 over 3
  • straight pi over 2 minus 2 over 3
  • straight pi over 2 minus 2 over 3
  • straight pi over 2 minus 2 over 3
145 Views

Advertisement

10.

Let the population of rabbits surviving at a time t be governed by the differential equation.fraction numerator dp left parenthesis straight t right parenthesis over denominator dt end fraction space equals space 1 half straight p left parenthesis straight t right parenthesis space minus 200 If p(0) = 100 then p(t) is equal to 

  • 400 minus 300 straight e to the power of straight t over 2 end exponent
  • 300 minus 200 straight e to the power of negative straight t over 2 end exponent
  • 600 minus 500 straight e to the power of straight t over 2 end exponent
  • 600 minus 500 straight e to the power of straight t over 2 end exponent


A.

400 minus 300 straight e to the power of straight t over 2 end exponent

Given differential equation dp over dt minus 1 half straight p left parenthesis straight t right parenthesis space equals space minus 200 is a linear differential equation
Here, p(t) = fraction numerator negative 1 over denominator 2 end fraction comma space straight Q space left parenthesis straight t right parenthesis space equals space minus space 200
 If space equals space straight e to the power of integral negative open parentheses 1 half close parentheses dt end exponent space equals space straight e to the power of negative 1 half end exponent
Hence, solution is 
p(t), IF = ∫Q(t)IF dt
straight p left parenthesis straight t right parenthesis. straight e to the power of negative straight t over 2 end exponent space equals space integral negative 200. straight e to the power of negative straight t over 2 end exponent dt
straight p left parenthesis straight t right parenthesis. straight e to the power of negative straight t over 2 end exponent space equals integral negative 200 space straight e to the power of negative straight t over 2 end exponent. dt
straight p left parenthesis straight t right parenthesis. straight e to the power of negative straight t over 2 end exponent space equals space 400 space straight e to the power of negative straight t over 2 end exponent space plus space straight K
rightwards double arrow space straight p left parenthesis straight t right parenthesis space equals space 400 space plus ke to the power of negative 1 half end exponent
If space straight p left parenthesis 0 right parenthesis space equals space 100 space comma then space straight k space equals negative 300
rightwards double arrow space straight p left parenthesis straight t 0 space equals space 400 space minus 300 to the power of straight t over 2 end exponent

147 Views

Advertisement
Advertisement