Previous Year Papers

Download Solved Question Papers Free for Offline Practice and view Solutions Online.

Test Series

Take Zigya Full and Sectional Test Series. Time it out for real assessment and get your results instantly.

Test Yourself

Practice and master your preparation for a specific topic or chapter. Check you scores at the end of the test.
Advertisement

 Multiple Choice QuestionsMultiple Choice Questions

131.

The equation (x - x1)(x - x2) + (y - y1)(y - y2) = 0 represents a circle whose centre is

  • x1 - x22, y1 - y22

  • x1 + x22, y1 + y22

  • (x1, y1)

  • (x2, y2)


132.

The circles x2 + y2 + 6x + 6y = 0 and x2 + y2 - 12x - 12y = 0

  • cut orthogonally

  • touch each other internally

  • intersect in two points

  • touch each other externally


133.

The two parabolas x2 = 4y and y2 = 4x meet in two distinct points. One of these is the origin and the other is

  • (2, 2)

  • (4, - 4)

  • (4, 4)

  • (- 2, 2)


134.

The vertex of the parabola x2 + 2y = 8x - 7 is

  • 92, 0

  • 4, 92

  • 2, 92

  • 4, 72


Advertisement
135.

If P(at2, 2at) be one end of a focal chord of the parabola y2 = 4ax, then the length of the chord is

  • at - 1t2

  • at - 1t

  • at + 1t

  • at + 1t2


136.

The length of the common chord of the parabolas y2 = x and x2 = y is

  • 22

  • 1

  • 2

  • 12


137.

The equation of the ellipse having vertices at (± 5, 0) and foci (± 4, 0) is

  • x225 + y216 = 1

  • 9x2 + 25y2 = 225

  • x29 + y225 = 1

  • 4x2 + 5y2 = 20


Advertisement

138.

The area included between the parabolas y2 = 4x and x2 = 4y is

  • 83 sq unit

  • 8 sq unit

  • 163 sq unit

  • 12 sq unit


C.

163 sq unit

We know that, the area ofregion bounded by the parabolas y2 = 4ax and x2 = 4by is 163ab sq unit.

Therefore, the area of region bounded by the parabolas y2 = 4x and x= 4y is 163 sq unit.

                a = 1, b = 1


Advertisement
Advertisement
139.

The locus of the centres of the circles which touch both the axes is given by

  • x2 - y2 = 0

  • x2 + y2 = 0

  • x2 - y2 = 1

  • x2 + y2 = 1


140.

The latusrectum of an ellipse is equal to one-half of its minor axis. The eccentricity of the ellipse is

  • 16

  • 32

  • 34

  • 12


Advertisement