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 Multiple Choice QuestionsMultiple Choice Questions

241.

In the given circuit the reading of voltmeter V1 and V2 are 300 V each. The reading to the voltmeter V3 and ammeter A are respectively

  • 150 V, 2.2 A

  • 220 V , 2.2 A

  • 220 V, 2.0 A

  • 220 V, 2.0 A

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242.

Consider the following two statements

A) Kirchhoff junction law follows from the conservation of charge.

B) Kirchhoff's loop law follows from the conservation of energy

Which of the following is correct?

  • Both (A) and (B) are wrong

  • (A) Is correct and (B) is wrong

  • (A) is wrong and (B) is correct

  • (A) is wrong and (B) is correct

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243.

The voltage gain of an amplifier with 9% negative feedback is 10. The voltage gain without feedback will be

  • 90

  • 10

  • 1.25

  • 1.25

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244.

A current  of 3 A flows through the 2 Ω resistor shown in the circuit. The power dissiated in the 5 Ω resistor is 

diagram

  • 4 W

  • 2 W

  • 1 W

  • 1 W

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245.

A wire of a certain material is stretched slowly by ten percent. Its new resistance and specific resistance become respectively

  • 1.2 times, 1.1 times

  • 1.21 times, same

  • both remain the same

  • both remain the same

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246.

The total power dissipated in watts in the circuit shown here is:

  • 16

  • 40

  • 54

  • 54

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247.

The resistance of an ammeter is 13 Ω  and its scale is graduated for a current up to 100 A. After an additional shunt has been connected to this ammeter it becomes possible to measure currents up to 750 A by this meter. The value of shunt resistance is.

  • 20 Ω

  • 2 Ω

  • 0.2 Ω

  • 0.2 Ω

690 Views

248.

A steady current of 1.5 A flows through a copper voltameter for 10 min. If the electrochemical equivalent of copper is 30 x 10-5 g C-1, the mass of copper  deposited on the electrode will be:

  • 0.40 g

  • 0.50 g

  • 0.67 g

  • 0.67 g

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249.

Three resistances P, Q, R each of 2 Ω and an unknown resistance S form the four arms of a Wheatstone's bridge circuit. When a resistance of 6 Ω is connected in parallel  to S the bridge gets balanced. What is the value of S? 

  • 2 Ω

  • 3 Ω

  • 6 Ω

  • 6 Ω

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250.

In the circuit shown, if a conducting wire is connected between points A and B, the current in this wire will



  • flow from A to B

  • flow in the direction which will be decided by the value of V

  • be zero

  • be zero


D.

be zero

Current will flow from higher to lower potential.
Resistances 4 space straight capital omega space and space 4 space straight capital omega are connected in series, so their effective resistance is                  straight R apostrophe space equals space 4 plus 4 space equals space 8 straight capital omega
  Similarly, 1 straight capital omega and 3 straight capital omega are in series
So,       straight R apostrophe apostrophe space equals space 1 plus 3 space equals space 4 straight capital omega
Now R' and R" will be in parallel, hence effective resistance
                          straight R space equals space fraction numerator straight R apostrophe space cross times space straight R " over denominator straight R apostrophe plus straight R apostrophe apostrophe end fraction
space space space space equals fraction numerator 8 cross times 4 over denominator 8 plus 4 end fraction space equals space 32 over 12 equals 8 over 3 straight capital omega
Current through the circuit, from Ohm's law
                         straight i space equals space straight V over straight R equals space fraction numerator 3 straight V over denominator 8 end fraction straight A
Let current straight i subscript 1 space and space straight i subscript 2 flow in the branches as shown:
therefore space space space space 8 straight i subscript 1 space equals space 4 straight i subscript 2
rightwards double arrow space space space space space straight i subscript 2 space equals space 2 straight i subscript 1
Also comma space space space space straight i space equals space straight i subscript 1 space plus space straight i subscript 2 space space space space space space space space space space space space space space space space space space space space... left parenthesis straight i right parenthesis
rightwards double arrow space space space space space space fraction numerator 3 straight V over denominator 8 end fraction space equals straight i subscript 1 plus 2 straight i subscript 1
rightwards double arrow space space space straight i subscript 1 space equals space straight V over 8 straight A
and space space straight i subscript 2 space equals space straight V over 4 straight A
 Potential space drop space at space straight A comma space straight V subscript straight A space equals space 4 space cross times space straight i subscript 1 space equals space fraction numerator 4 straight V over denominator 8 end fraction space equals space straight V over 2
Potential space drop space at space straight B comma space straight V subscript straight B space equals space 1 space cross times space straight i subscript 2 space equals space 1 cross times straight V over 4 space equals space straight V over 4
Since, drop of potential is greater in 4 straight capital omega resistance so. It will be at lower potential than B, hence, on connecting wire between points A and B, the current will flow from B to A.


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