In a transistor circuit, the base current changes from 30 µA to 90 µA. If the current gain of the transistor is 30%, the change in the collector current is
4 mA
2 mA
3.5 mA
1.8 mA
In a full wave rectifier, input AC current has a frequency v. The output frequency of current is
v
2 v
None of these
A full wave rectifier circuit along with the output is shown in the figure. The contribution (s) from the diode 1 is ( are )
C
A , C
B , D
A, B , C , D
Two identical p-n junctions may be connected in series with a battery in three ways as shown in the figure.
The potential drops across the two n-p junctions are equal in
circuit 1 and circuit 2
circuit 2 and circuit 3
circuit 3 and circuit 1
circuit 1 only
A transistor is used in common emitter mode as an amplifier, then
the base emitter junction is forward unbiased
the base emitter junction is reverse biased
the input signal is connected in series with the voltage applied to bias of the base emitter junction
the input signal is connected in series with the voltage applied to bias the emitter collector junction
A transistor is connected in CE configuration. The supply to the collector is 8 V and the voltage drop across a resistor of 400 Ω in the collector circuit is 0.5 V. If the current gain factor is = 0.96 then, the base current will be nearly
52 µA
42 µA
32 µA
26 µA
The width of depletion layer in a p-n junction diode
increases when a forward bias is applied
increases when a reverse bias is applied
decreases when a reverse bias is applied
remains same irrespective of bias voltage
To get an output y = 1 from the circuit shown the inputs A, B and C must be respectively.
0, 1, 0
1, 0, 0
1, 0, 1
1, 1, 0
In a common emitter (CE) amplifier having a voltage gain G, the transistor used has transconductance 0.03 mho and current gain 25. If the above transistor is replaced with another one with transconductance 0.02 mhoand current gain 20, the voltage gain will be
1.5 G