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 Multiple Choice QuestionsMultiple Choice Questions

11.

If the area of the base, height and volume of a right prism be  and 7200 cm3 respectively, then the value of P will be

  • 4
  • square root of 3
  • square root of 3
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12.

A circular swimming pool is surrounded by a concrete wall 4m wide. If the area of the concrete wall surrounding the pool is 11 over 25 that of the pool, then the radius (in m) of the pool is

  • 20

  • 30

  • 16

  • 16


A.

20



Area of pool  = A
therefore    Area of wall = fraction numerator 11 straight A over denominator 25 end fraction
Area of (pool + wall) = straight pi left parenthesis straight r plus 4 right parenthesis squared comma Area of pool = πr squared
Area of wall = Area of (pool + wall) - Area of pool
  fraction numerator 11 space cross times space πr squared over denominator 25 end fraction space equals space straight pi left parenthesis straight r plus 4 right parenthesis squared space minus space πr squared
11 over 25 cross times πr squared space equals space straight pi left parenthesis straight r squared plus 16 plus 8 straight r right parenthesis minus πr squared space equals space πr squared plus 16 straight pi plus 8 πr minus πr squared
11 over 25 πr squared space equals space 8 straight pi left parenthesis 2 plus straight r right parenthesis
   fraction numerator 11 straight r squared over denominator 25 end fraction space equals space 8 left parenthesis 2 plus straight r right parenthesis space rightwards double arrow space space space 11 straight r squared space equals space 200 space cross times space 2 space plus space 200 straight r
rightwards double arrow space space 11 straight r squared minus 200 straight r minus 400 space equals space 0 space space rightwards double arrow space space 11 straight r squared minus 220 straight r plus 20 straight r minus 400 space equals space 0

rightwards double arrow space space 11 straight r left parenthesis straight r minus 20 right parenthesis space space plus 20 left parenthesis straight r minus 20 right parenthesis space equals space 0
rightwards double arrow space space space space space space left parenthesis straight r minus 20 right parenthesis thin space left parenthesis 11 straight r plus 20 right parenthesis space equals space 0 space space rightwards double arrow space space straight r space equals space 20 space space equals space 0 space space space therefore space space straight r space equals space 20 space straight m

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13.

A conical iron piece having diameter 28 cm and height 30cm is totally immersed into the water of a cylindrical vessel, resulting in the rise of water level by 6.4 cm. The diameter (in cm) of the vessel is

  • 3.5 

  • 35 over 2
  • 35

  • 35

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14.

The area of the iron sheet required to prepare a cone 24 cm high with base radius 7 cm is open parentheses Take space straight pi space equals space 22 over 7 close parentheses.

  • 708 cm2

  • 804 cm2

  • 704 cm2

  • 704 cm2

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15.

A rectangular tin sheet is 12 cm long and 5 cm broad. It is rolled along its length to form a cylinder by making the opposite edges just to touch each other. Then, the volume of the cylinder is

  • 180/π cm3

  • 120/π cm3

  • 100/π cm3

  • 60/π cm3

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16.

The radius of a sphere and hemisphere are same. The ratio of their total surface areas is

  • 3 : 1

  • 2 : 1

  • 3 : 2

  • 3 : 2

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17.

The height of a right circular cylinder is twice its radius of the base. If its height be 6 times its radius of the base, then the volume of the cylinder will be 539 cm3 more. Assuming straight pi space equals space 22 over 7 comma space the height of the cylinder is

  • 5 cm

  • 7 cm

  • 9 cm

  • 9 cm

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18.

A sphere of radius 5 cm is melted to form a cone with base of same radius. The height (in cm) of the cone is

  • 5

  • 10

  • 20

  • 20

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19.

The volume of metallic cylindrical pipe of uniform thickness is 748 cm3. Its length is 14 cm and its external radius is 9 cm. The thickness of the pipe is

  • 0.5 cm

  • 1.5 cm

  • 1 cm

  • 1 cm

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20.

If the sum of radius and height of a solid cylinder is 20 cm and its total surface area is 880 cm2 then its volume is

  • 1760 cm3

  • 8800 cm3

  • 2002 cm3

  • 2002 cm3

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