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 Multiple Choice QuestionsMultiple Choice Questions

61.

Walking 6/7 of his usual speed, a man is 12 min too late. The usual time taken by him to cover that distance is

  • 1 hr

  • 1 h 12 min

  • 1 h 15 min

  • 1 h 20 min

54 Views

62.

A person travels 285 km in 6h. In the first part of the journey, he travels at 40 km/h by bus. In the second part, he travels at 55 km/h by train. The distance travelled by train is

  • 165 km

  • 615 km

  • 561 km

  • 156 km

54 Views

63.

A certain distance is covered at a certain speed. If half of this distance is covered in double the time, the ratio of the two speeds is

  • 4 : 1

  • 1 : 4

  • 2 : 1

  • 1 : 2

39 Views

64.

Two cars are moving with speeds v1 and v2 towards a crossing along two roads. If their distances from the crossing be 40 m and 50 m at an instant of time, then they do not collide, if their speeds are such that

  • v1 : v2 ≠  4 : 5

  • v1 : v2 ≠  5 : 4

  • v1 : v2 ≠  25 : 16

  • v1 : v2 ≠  16 : 25

36 Views

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65.

A, B and C walk 1 km in 5 min, 8 min and 10 min, respectively. C starts walking from a point, at a certain time, B starts from the same point 1 min later and A starts from the same point 2 min later than C. Then, A meet B and C at times

  • 2 min, 3 min

  • 4 over 3 min comma space space 3 space min

  • 2 min,  5 over 3 min

  • 1 min, 2 min

38 Views

66.

A man rides at the rate of 18 km/h but stops for 6 min to change horses at the end of every 7th km. The time that he will take to cover a distance of 90 km is

  • 6 h

  • 6 h 12 min

  • 6 h 18 min

  • 6 h 24 min

49 Views

67.

A farmer travelled a distance of 61 km in 9h. He travelled partly on foot at the rate of 4 km/h and partly on bicycle at the rate of 9 km/h. The distance travelled on foot is

  • 14 km

  • 17 km

  • 15 km

  • 16 km


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68.

Walking at the rate of 4 km/h a man covers certain distance in 2 h 45 min. Running at a speed of 16.5 km/h the man will cover the same distance in how many minutes?

  • 45

  • 50

  • 40

  • 35


C.

40

Case I,
Distance  = Speed x Time
               equals space 4 space cross times space open parentheses 2 space plus space 45 over 60 close parentheses
equals space 4 space cross times space open parentheses 2 space plus space 3 over 4 close parentheses
equals space 4 space cross times space open parentheses 11 over 4 close parentheses
equals space 11 space km
Case II,
Distance = 11 km
Speed  = 16.5 km/h
Time space equals space Distance over Speed space equals space fraction numerator 11 over denominator 16.5 end fraction space equals space open parentheses fraction numerator 11 space cross times space 10 over denominator 165 end fraction cross times space 60 space close parentheses min space equals space 40 space min



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69.

A man travelled a distance of 60 km in 7 hours. He travelled partly on foot @ 6km/h and partly on bicycle @ 12 km/h. What is the distance (in km) travelled on foot?

  • 15 km

  • 9 km

  • 48 km

  • 24 km


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