What would be the equation of the line, which intercepts x-axis at -5 and perpendicular to the line y = 2x - 3?
x - 2y = -5
x + 2y = 5
x + 2y = -5
x - 2y = 5
The area of the triangle formed by the graphs of the equations x = 4, y = 3 and 3x + 4y = 12 is
4 sq units
12 sq units
6 sq units
6 sq units
The coordinates of the vertices of a right angled triangle are P(3, 4), Q(7, 4) and R(3, 8), the right angle being at P. The coordinates of the orthocentre of are
(3, 4)
(7, 4)
(3, 8)
(3, 8)
The area (in square units) of the triangle formed by the graphs of the equations x = 4, y = 3 and 3x + 4y = 12 is
24
12
6
6
If the ordinate and abscissa of the point (k, 2k -1) be equal, then the value of k is
0
-1
1
1
Area of the triangle formed by the graph of the straight lines x - y = 0, x + y = 2 and x-axis is
1 sq unit
2 sq units
1 sq units
None of these
The graphs of x + 2y = 3 and 3x - 2y = 1 meet the Y-axis at two points having distance
1 unit
1 unit
The value of k for which the graphs of (k - 1)x + y - 2 = 0 and (2 - k)x - 3y + 1 = 0 are parallel is
2
2
The area of the triangle formed by the straight line 3x + 2y = 6 and the co-ordinate axes is
3 square units
6 square units
4 square units
4 square units
The length of the intercept of the graph of the equation 9x - 12y = 108 between the two axes is
15 units
9 units
12 units
18 units