Which one of the following is correct?
The equilibrium constant (Kc) is independent of temperature
The value of Kc is independent of initial concentrations of reactants and products
At equilibrium, the rate of the forward reaction is twice the rate of the backward reaction.
The equilibrium constant (Kc) for the reaction
Which of the following statement is correct ?
BCl3 and AlCl3 are both Lewis acids and AlCl3 is stronger than BCl3
BCl3 and AlCl3 are both equally strong Lewis acid
Both BCl3 and AlCl3 are not Lewis acid
BCl3 and AlCl3 are both Lewis acids and BCl3 is stronger than AlCl3
For the reaction, 2HI (g) H2 (g) + I2 (g) the degree of dissociation (α) of HI (g) is related to equilibrium constant Kp by the expression
Rank the following in decreasing order of basic strength
(i) CH3-CH2-C≡C-
(ii) CH3-CH2-S-
(iii) CH3-CH2-CO
(iv) CH3-CH2-O-
(iv) > (i) > (ii) > (iii)
(i) > (iv) > (ii) > (iii)
(i) > (iv) > (iii) > (ii)
(ii) > (i) > (iv) > (iii)
In the following compounds, the decreasing order of basic strength will be:
(C2H5)2NH > NH3 > C2H5NH2
(C2H5)2NH > C2H5NH2 > NH3
C2H5NH2 > NH3 > (C2H5)2NH
NH3 > C2H5NH2 > (C2H5)2NH
For the following reactions, equilibrium constans are given:
S(s) + O2(g) SO2(g); K1 = 1052
2S(s) + 3O2(g) SO3(g); K2 = 10129
The equilibrium constant for the reaction,
2SO2(s) + O2(g) SO3(g)
10181
1077
10154
1025
In an acid-base titration, 0.1 M HCl solution was added to the NaOH solution of unknown strength. Which of the following correctly shows the change of pH of the titration mixture in this experiment ?
(D)
(A)
(C)
(B)
Consider the following statements
a) The pH of a mixture containing 400mL of 0.1M H2SO4 and 400 mLof 0.1M NaOH will be approximately 1.3.
b) Ionic product of water is temperature dependent.
c) A monobasic acid with Ka=10-5 has a pH=5. The degree of dissociation of this acid is 50%.
d) The Le Chatelier’s Principle is not applicable to common-ion effect.
The correct statements are
b and c
a,b and d
a,b, and c
a and b
The pH of a 0.02 M NH4Cl solution will be: [ given Kb(NH4OH) = 10-5 and log 2= 0.301]
5.35
2.65
4.65
4.35