Aldehydes, Ketones and Carboxylic Acids

The reagents to carry out the following conversion are

• HgSO₄/dil H₂SO₄

• BH₃; H₂O₂/NaOH

• OsO₄; HIO₄

• NaNH₂ /CH₃I; HgSO₄/dil H₂SO_4.

In the following reaction, the product  E is

The intermediate J in the following Wittig reaction is

In the following species, the one which is likely to be the intermediate during benzoin condensation of benzaldehyde is

Baeyer's reagent is

• alkaline potassium permanganate

• acidified potassium permanganate

• neutral potassium permanganate

• alkaline potassium manganate

The best method for preparation of Me₃CCN is

• to react with Me₃COH with HCN

• to react with Me₃CBr with NaCN

• to react with Me₃CMgBr with ClCN

• to react Me₃CLi with NH₂CN

Upon treatment with I₂ and aqueous NaOH, which of the following compounds will form iodoform?

• CH₃CH₂CH₂CH₂CHO

• CH₃CH₂COCH₂CH₃

• CH₃CH₂CH₂CH₂CH₂OH

• CH₃CH₂CH₂CH₂(OH)CH₃

Upon treatment with Al(OEt)₃ followed by usual reactions (work up), CH₃CHO will produce

• only CH₃COOCH₂CH₃

• A mi xture of CH₃COOH and EtOH

• only CH₃COOH

• only EtOH

Identify the method by which Me₃CCO₂H can be prepared.

• Treating 1 mole of MeCOMe with 2 moles of MeMgI

• Treating 1 mole of MeCO₂Me with 3 moles of MeMgI

• Treating 1 mole of MeCHO with 3 moles of MeMgI

• Treating 1 mole of dry ice with 1 mol of Me₃CMgI

The most contributing tautomeric enol form of MeCOCH₂CO₂ Et is 

• ${\mathrm{CH}}_2=\mathrm{C}\left(\mathrm{OH}\right){\mathrm{CH}}_2{\mathrm{CO}}_2\mathrm{Et}$

• $\mathrm{MeC}\left(\mathrm{OH}\right)={\mathrm{CHCO}}_2\mathrm{Et}$

• $\mathrm{MeCOCH}=\mathrm{C}\left(\mathrm{OH}\right)\mathrm{OEt}$

• ${\mathrm{CH}}_2=\mathrm{C}\left(\mathrm{OH}\right)\mathrm{CH}=\mathrm{C}\left(\mathrm{OH}\right)\mathrm{OEt}$