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 Multiple Choice QuestionsMultiple Choice Questions

201.

In the following network, potential at O is

               

  • 4 V

  • 3 V

  • 6 V

  • 4.8 V


202.

Effective resistance between A and B in the following circuit                                 

  • 10 Ω

  • 20 Ω

  • 5 Ω

  • 203 Ω


203.

Two heating coils of resistances 10 Ω and 20 Ω are connected in parallel and connected to a battery of emf 12 V and internal resistance 1 Ω. The power consumed by them are in the ratio

  • 1 : 4

  • 1 : 3

  • 2 : 1

  • 4 : 1


204.

Of the following graphs, the one that correctly represents the I-V characteristics of a 'Ohmic device' is


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205.

The working of magnetic braking of trains is based on

  • eddy current

  • pulsating current

  • alternating current

  • steady current


206.

A cylindrical conductor of diameter 0.1 mm carries a current of 90 mA. The current density (in Am-2) is (π ≈ 3)

  • 12 × 107

  • 3 × 106

  • 6 × 106

  • 2.4 × 107


207.

A straight wire of length 50 cm carrying a current of 2.5 A is suspended in mid-air by a uniform magnetic field of 0.5 T (as shown in figure). The mass of the wire is (g = 10 ms-2)

                

  • 250 gm

  • 125 gm

  • 62.5 gm

  • 100 gm


208.

In meter bridge experiment, with a standard resistance in the right gap and a resistance coil dipped in water (in a beaker) in the left gap, the balancing length obtained is 'l'. If the temperature of water is increased, the new balancing

  • < 1

  • > 1

  • = 0

  • = 1


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209.

The power dissipated in 3 Ω resistance in the following circuit is

                 

  • 0.25 W

  • 0.75 W

  • 1 W

  • 0.5 W


B.

0.75 W

The equivalent circuit of the given circuit will be

             

From circuit,  1R = 13 + 16                           = 2 + 16 = 36 ΩR1 = 2 Ω

                

R2 = R1 + R2 + R4

    = 2 + 2 + 4

    = 8 Ω

The internal resistance of battery = 1 Ω

So, the equivalent resistance of circuit

    = 8 Ω + 1 Ω

    = 9 Ω

The current in the circuit

I = VR = 4.59  = 12 A

The power dissipated in 3 Ω resistance

P = I2 × R   = 122 × 3   = 14 × 3   = 0.75 W


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210.

The value of I in the figure shown below is

               

  • 21 A

  • 4 A

  • 8 A

  • 19 A


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