Download Solved Question Papers Free for Offline Practice and view Solutions Online.

Take Zigya Full and Sectional Test Series. Time it out for real assessment and get your results instantly.

Practice and master your preparation for a specific topic or chapter. Check you scores at the end of the test.

Advertisement

Advertisement

11.

If 0.1 J of energy is stored for the flow of current of 0.2 A in an inductor, then its inductance value is

5 H

0.5 H

5 mH

50 H

12.

The self-inductance of a long solenoid carrying current is independent of

its length

the current

its cross-sectional area

magnetic permeability of the core

13.

The polarity of induced emf is given by

Ampere's circuital law

Biot-Savart's law

Lenz's law

Fleming's right hand rule

14.

A conducting ring of radius 1 m kept in a uniform magnetic field B of 0.01 T, rotates uniformly with an angular velocity 100 rads^{-1 }with its axis of rotation perpendicular to B. The maximum induced emf in it is

$1.5\mathrm{\pi}\mathrm{V}$

$\mathrm{\pi}\mathrm{V}$

$2\mathrm{\pi}\mathrm{V}$

$0.5\mathrm{\pi}\mathrm{V}$

Advertisement

15.

The self-inductance of an air core solenoid of 100 turns is 1 mH. The self-inductance of another solenoid of 50 turns (with the same length and cross-sectional area) with a core having relative permeability 500 is

125 mH

24 mH

60 mH

30 mH

16.

The magnetic flux linked with a coil of N turns of area of cross-section A held with its plane parallel to the field B is

$\frac{\mathrm{NAB}}{2}$

NAB

$\frac{\mathrm{NAB}}{4}$

0

17.

Two identical coaxial coils P and Q carrying equal amount of current in the same direction are brought nearer. The current in

P increases while in Q decreases

Q increases while in P decreases

both P and Q increases

both P and Q decreases

18.

The self inductance of a long solenoid cannot be increased by

increases its area of cross section

increasing its length

increasing the current through it

increasing the number of turns in it

Advertisement

19.

A 5O Hz AC current of peak value 2 A flows through one of the pair of coils. If the mutual inductance between the pair of coils is 150 mH, then the peak value of voltage induced in the second coil is

$30\mathrm{\pi V}$

$60\mathrm{\pi V}$

$15\mathrm{\pi V}$

$300\mathrm{\pi V}$

20.

In the total electromagnetic energy falling on a surface is U, then the total momentum delivered (for complete absorption) is

$\frac{\mathrm{U}}{\mathrm{c}}$

cU

$\frac{\mathrm{U}}{{\mathrm{c}}^{2}}$

c

^{2}U

Advertisement