Which of the following reactions will yield 2, 2-dibromopropane?
CH3 – C ≡ CH + 2HBr →
CH3CH = CHBr + HBr →
CH ≡ CH + 2HBr →
CH ≡ CH + 2HBr →
A.
CH3 – C ≡ CH + 2HBr →
The IUPAC name of
1, 1-diethyl-2-dimethylpentane
4, 4-dimethyl-5, 5-diethylpentane
5, 5-diethyl-4, 4-dimethylpentane
5, 5-diethyl-4, 4-dimethylpentane
D.
5, 5-diethyl-4, 4-dimethylpentane
Reaction of trans-2-phenyl-1-bromocyclopentane on reaction with alcoholic KOH produces
4-phenylcyclopentene
2-phenylcyclopentene
1-phenylcyclopentene
1-phenylcyclopentene
D.
1-phenylcyclopentene
Which of the following is the correct order of decreasing SN2 reactivity?
RCH2X > R3CX > R2CHX
RCH2X > R2CHX > R3CX
R3CX > R2CHX >RCH2X
R3CX > R2CHX >RCH2X
B.
RCH2X > R2CHX > R3CX
More is the steric hindrance at the carbon bearing the halogen, lesser is the SN2 reactivity.
The organic chloro compound, which shows complete stereochemical inversion during a SN2 reaction,is
(C2H5)2CHCl
(CH3)3CCl
(CH3)2CHCl
(CH3)2CHCl
B.
(CH3)3CCl
D.
(CH3)2CHCl
For SN2 reaction, the C atom is least hindered towards the attack of nucleophile in the case of (CH3Cl).
Phenyl magnesium bromide reacts with methanol to give
a mixture of anisole and Mg(OH)Br
a mixture of benzene and Mg(OMe)Br
a mixture of toluene and Mg(OH)Br
a mixture of toluene and Mg(OH)Br
B.
a mixture of benzene and Mg(OMe)Br
Toluene is nitrated and the resulting product is reduced with tin and hydrochloric acid. The product so obtained is diazotised and then heated with cuprous bromide. The reaction mixture so formed contains
mixture of o− and p−bromotoluenes
mixture of o− and p−dibromobenzenes
mixture of o− and p−bromoanilines
mixture of o− and p−bromoanilines
A.
mixture of o− and p−bromotoluenes
Presence of a nitro group in a benzene ring -
activates the ring towards electrophilic substitution
renders the ring basic
deactivates the ring towards nucleophilic substitution
deactivates the ring towards nucleophilic substitution
D.
deactivates the ring towards nucleophilic substitution
The treatment of CH3MgX with CH3C≡C−H produces
CH3−CH=CH2
CH3C≡C−CH3
D.
CH3-MgX + CH3-C≡C-H→ CH4