જો  અને સદિશો (1, a, a2) ; (1, b, b2) અને (1, c, c2) એ સમતલીય હોય, તો abc = ......   from Mathematics નિશ્વાયક

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Gujarati JEE Mathematics : નિશ્વાયક

Multiple Choice Questions

1. a ની કઈ કિંમત માટે સમીકરણ સંહિત
ax + y + z = a - 1
x+ ay + z = a - 1
x + y + az = a - 1 ને એક પણ ઉકેલ નથી.
  • -2
  • 2 અથવા 1
  • -2 સિવાય
  • 1

2.
જો a < 0 અને ax2 + 2bx + c નો વિવેચક ઋણ હોય, તો open vertical bar table row bold a bold b cell bold ax bold plus bold b end cell row bold b bold c cell bold bx bold plus bold c end cell row cell bold ax bold plus bold b end cell cell bold bx bold plus bold c end cell bold 0 end table close vertical bar નું મૂલ્ય ......... છે.
  • ઋણ

  • (ac-b2) (ax2+2bx+c)
  • 0
  • ધન

3. જો 1, w, w2 એ 1 નાં ઘન મુળ હોય, તો open vertical bar table row bold 1 cell bold w to the power of bold n end cell cell bold w to the power of bold 2 bold n end exponent end cell row cell bold w to the power of bold n end cell cell bold w to the power of bold 2 bold n end exponent end cell bold 1 row cell bold w to the power of bold 2 bold n end exponent end cell bold 1 cell bold w to the power of bold n end cell end table close vertical bar bold space bold equals bold space bold. bold. bold. bold. bold. bold. bold. bold. bold. bold. bold.
  • w2
  • w
  • 0
  • 1

4.
જો a2+ b2 + c2 + 2 = 0 અને bold f bold left parenthesis bold x bold right parenthesis bold space bold equals bold space open vertical bar table row cell bold 1 bold plus bold a to the power of bold 2 bold x end cell cell bold left parenthesis bold 1 bold plus bold b to the power of bold 2 bold right parenthesis bold x end cell cell bold left parenthesis bold 1 bold plus bold c to the power of bold 2 bold right parenthesis bold x end cell row cell bold left parenthesis bold 1 bold plus bold a to the power of bold 2 bold right parenthesis bold x end cell cell bold 1 bold plus bold b to the power of bold 2 bold x end cell cell bold left parenthesis bold 1 bold plus bold c to the power of bold 2 bold right parenthesis bold x end cell row cell bold left parenthesis bold 1 bold plus bold a to the power of bold 2 bold right parenthesis bold x end cell cell bold left parenthesis bold 1 bold plus bold b to the power of bold 2 bold right parenthesis bold x end cell cell bold 1 bold plus bold c to the power of bold 2 bold x end cell end table close vertical bar તો, f(x) એ  ..........ઘાતવાળી બહુપદી થાય.
  • 3
  • 2
  • 0
  • 1

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5. જો bold D bold space bold equals bold space open vertical bar table row bold 1 bold 1 bold 1 row bold 1 cell bold 1 bold plus bold x end cell bold 1 row bold 1 bold 1 cell bold 1 bold plus bold y end cell end table close vertical bar જ્યાં x ≠ 0, y ≠ 0 તો D એ ....... x, y ∈ N
  • x અને y વડે વિભાજ્ય છે.

  • x વડે વિભાજ્ય છે પરંતુ y વડે વિભાજ્ય નથી. 
  • x વડે વિભાજ્ય નથી પરંતુ y વડે વિભાજ્ય છે. 
  • x અને y પૈકી એક પણ વડે વિભાજ્ય નથી.

6.
જો x + 2ay + az = 0; x + 3by + bz = 0, x + 4cz + cz = 0 સમીકરણો સુસંગત હોય, તો a, b, c એ ........ છે.
  • સ્વરિત શ્રેણીમાં 

  • સમાંતર શ્રેણીમાં 
  • સમગુણોત્તર શ્રેણીમાં 
  • ત્રણમાંથી એક પણ નહી

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7.
જો open vertical bar table row bold a cell bold a to the power of bold 2 end cell cell bold 1 bold plus bold a to the power of bold 3 end cell row bold b cell bold b to the power of bold 2 end cell cell bold 1 bold plus bold b to the power of bold 3 end cell row bold c cell bold c to the power of bold 2 end cell cell bold 1 bold plus bold c to the power of bold 3 end cell end table close vertical bar bold space bold equals bold space bold 0 અને સદિશો (1, a, a2) ; (1, b, b2) અને (1, c, c2) એ સમતલીય હોય, તો abc = ......  
  • 1
  • 2
  • 0
  • -1

D.

-1

Tips: -

open vertical bar table row bold a cell bold a to the power of bold 2 end cell cell bold 1 bold plus bold a to the power of bold 3 end cell row bold b cell bold b to the power of bold 2 end cell cell bold 1 bold plus bold b to the power of bold 3 end cell row bold c cell bold c to the power of bold 2 end cell cell bold 1 bold plus bold c to the power of bold 3 end cell end table close vertical bar bold space bold equals bold space open vertical bar table row bold a cell bold a to the power of bold 2 end cell bold 1 row bold b cell bold b to the power of bold 2 end cell bold 1 row bold c cell bold c to the power of bold 2 end cell bold 1 end table close vertical bar bold space bold plus bold space open vertical bar table row bold a cell bold a to the power of bold 2 end cell cell bold a to the power of bold 3 end cell row bold b cell bold b to the power of bold 2 end cell cell bold b to the power of bold 3 end cell row bold c cell bold c to the power of bold 2 end cell cell bold c to the power of bold 3 end cell end table close vertical bar bold space bold equals bold space bold 0 bold space bold space bold space bold space bold space bold space bold space bold space bold space bold space bold space bold space bold space bold space bold space bold space bold space bold space bold space bold space bold left parenthesis bold C subscript bold 12 bold right parenthesis end subscript


bold therefore bold space bold minus open vertical bar table row bold 1 cell bold a to the power of bold 2 end cell bold a row bold 1 cell bold b to the power of bold 2 end cell bold b row bold 1 cell bold c to the power of bold 2 end cell bold c end table close vertical bar bold space bold plus bold space bold abc bold space open vertical bar table row bold 1 bold a cell bold a to the power of bold 2 end cell row bold 1 bold b cell bold b to the power of bold 2 end cell row bold 1 bold c cell bold c to the power of bold 2 end cell end table close vertical bar bold space bold equals bold space bold 0 bold space bold space bold space bold space bold space bold space bold space bold space bold space bold space bold space bold space bold space bold space bold space bold R subscript bold 1 open parentheses bold 1 over bold a close parentheses bold comma bold space bold R subscript bold 2 open parentheses bold 1 over bold b close parentheses bold comma bold space bold R subscript bold 3 open parentheses bold 1 over bold c close parentheses bold space bold space bold space bold space bold space bold space bold space bold space bold space bold space bold space bold space bold space bold space bold left parenthesis bold C subscript bold 23 bold right parenthesis

bold therefore bold space open vertical bar table row bold 1 bold a cell bold a to the power of bold 2 end cell row bold 1 bold b cell bold b to the power of bold 2 end cell row bold 1 bold c cell bold c to the power of bold 2 end cell end table close vertical bar bold space bold plus bold space bold abc bold space open vertical bar table row bold 1 bold a cell bold a to the power of bold 2 end cell row bold 1 bold b cell bold b to the power of bold 2 end cell row bold 1 bold c cell bold c to the power of bold 2 end cell end table close vertical bar bold space bold equals bold space bold 0 bold space

bold therefore bold space bold left parenthesis bold abc bold space bold plus bold space bold 1 bold right parenthesis bold space open vertical bar table row bold 1 bold a cell bold a to the power of bold 2 end cell row bold 1 bold b cell bold b to the power of bold 2 end cell row bold 1 bold c cell bold c to the power of bold 2 end cell end table close vertical bar bold space bold equals bold space bold 0

આપેલ સદિશો સમતલીય છે. આથી open vertical bar table row bold 1 bold a cell bold a to the power of bold 2 end cell row bold 1 bold b cell bold b to the power of bold 2 end cell row bold 1 bold c cell bold c to the power of bold 2 end cell end table close vertical bar bold space bold not equal to bold space bold 0 bold space

∴ abc + 1 = 0 

∴ abc = -1

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8. જો s = p + q + r, તો open vertical bar table row cell bold s bold plus bold r end cell bold p bold q row bold r cell bold s bold plus bold p end cell bold q row bold r bold p cell bold s bold plus bold q end cell end table close vertical bar ની કિંમત ....... છે.
  • s3
  • 2s3
  • 2s2
  • 3s3

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9. જો open vertical bar table row bold a bold b cell bold ax bold plus bold by end cell row bold b bold c cell bold ax bold plus bold cy end cell row cell bold ax bold plus bold by end cell cell bold bx bold plus bold cy end cell bold 0 end table close vertical bar bold space bold equals bold space bold 0
 અને ax2 + 2bxy + cy2 ≠ 0 તો.........  
  • a, b, cસમગુણોત્તર શ્રેણીમાં છે.

  • a, b, c સમાંતર શ્રેણીમાં છે. 
  • a, b, c સ્વરિત શ્રેણીમાં છે. 
  • a, b, c એ સમગુણોત્તર, સમાંતર કે સ્વરિત શ્રેણીમાં નથી.

10. જો, w એ 1 નું ઘન મૂળ હોય, અને w ≠ 1 open vertical bar table row bold 1 cell bold 1 bold plus bold i bold plus bold w to the power of bold 2 end cell cell bold w to the power of bold 2 end cell row cell bold 1 bold minus bold i end cell cell bold minus bold 1 end cell cell bold w to the power of bold 2 bold minus bold 1 end cell row cell bold minus bold i end cell cell bold minus bold 1 bold plus bold w bold minus bold i end cell cell bold minus bold 1 end cell end table close vertical bar bold space bold equals bold space bold. bold. bold. bold. bold. bold. bold. bold. bold space
  • w2
  • w
  • 1
  • 0

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