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Gujarati JEE Physics : કાયનેમેટિક્સ

Multiple Choice Questions

1. $bold rightwards arrow for bold A of bold space bold equals bold space bold 5 bold i with bold hat on top bold space bold plus bold space bold 7 bold j with bold hat on top bold space bold minus bold space bold 3 bold k with bold hat on top$ અને $bold rightwards arrow for bold B of bold space bold equals bold space bold minus bold 2 bold i with bold hat on top bold space bold plus bold space bold m bold j with bold hat on top bold space bold plus bold space bold 6 bold k with bold hat on top$ પરસ્પર લંબ હોય, તો m = ......

-4
4
1
3

2. $bold rightwards arrow for bold A of bold space bold equals bold space bold 2 bold space bold i with bold hat on top bold space bold minus bold space bold j with bold hat on top bold space bold plus bold space bold 3 bold space bold k with bold hat on top$ અને $bold rightwards arrow for bold B of bold space bold equals bold space bold i with bold hat on top bold space bold plus bold space bold 2 bold space bold j with bold hat on top bold space bold minus bold space bold k with bold hat on top$ હોય, તો $bold rightwards arrow for bold A of bold space bold cross times bold space bold rightwards arrow for bold B of$ ની દિશામાંનો એકમ સદિશ ....... .

$fraction numerator 1 over denominator square root of 3 end fraction space left parenthesis space i with hat on top space plus space j with hat on top space plus space k with hat on top space right parenthesis$
$straight i with hat on top space minus space j with hat on top space plus space k with hat on top$
$fraction numerator 1 over denominator square root of 3 end fraction space left parenthesis space i with hat on top space plus space j with hat on top space plus space k with hat on top space right parenthesis$
$fraction numerator 1 over denominator square root of 14 end fraction space left parenthesis 3 space i with hat on top space plus space j with hat on top space plus space 2 space k with hat on top space right parenthesis$

3. $bold rightwards arrow for bold A of$ અને $bold rightwards arrow for bold B of$ નો સરવાળા સદિશ $bold rightwards arrow for bold R of$ એ $bold rightwards arrow for bold A of$ સાથે $bold alpha$ કોણ અને $bold rightwards arrow for bold B of$ સાથે $bold beta$ કોણ બનાવતો હોય, તો

હંમેશાં $straight alpha space greater than space straight beta$
જો A > B હોય, તો $bold alpha bold space bold less than bold space bold beta$
જો A < B હોય, તો $bold alpha bold space bold less than bold space bold beta$
જો A = B હોયા, તો $straight alpha space greater than space straight beta$

4. $bold vertical line bold space bold rightwards arrow for bold A of bold space bold plus bold space bold rightwards arrow for bold B of bold thin space bold vertical line bold space bold equals bold space bold vertical line bold rightwards arrow for bold A of bold vertical line bold space bold equals bold space bold vertical line bold rightwards arrow for bold B of bold vertical line$ હોય, તો $bold rightwards arrow for bold A of$ અને $bold rightwards arrow for bold B of$ વચ્ચેનો ખૂણો ......

$0 degree$
$120 degree$
$90 degree$
$30 degree$

5. $bold rightwards arrow for bold A of bold space bold equals bold space bold 4 bold space bold i with bold hat on top bold space bold plus bold space bold 3 bold j with bold hat on top bold space bold minus bold space bold k with bold hat on top$ અને $bold rightwards arrow for bold B of bold space bold equals bold space bold i with bold hat on top bold space bold plus bold space bold 2 bold space bold j with bold hat on top bold space bold plus bold space bold k with bold hat on top bold space$ થી રચાતા ત્રિકોણનું ક્ષેત્રફળ ........... એકમ.

$5 square root of 3$
$10 square root of 3$
$fraction numerator 5 square root of 3 over denominator 2 end fraction$
$fraction numerator square root of 3 over denominator 2 end fraction$

fraction numerator 5 square root of 3 over denominator 2 end fraction

bold rightwards arrow for bold A of

અને $bold rightwards arrow for bold B of$ ના મૂલ્ય અનુકમે 10 એકમ અને 20 એકમ છે. જો આ બે સદિશો વચ્ચે 30 $degree$ નો ખૂણો રચાતો હોય, તો પરિણામી સદિશ(R) નું મૂલ્ય ......... એકમ અને પરિમાણી સદિશ $open parentheses bold rightwards arrow for bold R of close parentheses$ નો $bold rightwards arrow for bold A of$ સાથેનો ખૂણો ...... મળે.
( $square root of bold 3 bold space bold equals bold space bold 1 bold. bold 7$ લો)

30 એકમ, 30 $degree$
10 એકમ, 30 $degree$
29 એકમ, 30 $degree$ 30'
39 એકમ, 30 $degree$ 30'

7. $bold rightwards arrow for bold A of$ અને $bold rightwards arrow for bold B of$ માટે, $bold vertical line bold space bold rightwards arrow for bold A of bold space bold cross times bold space bold rightwards arrow for bold B of bold space bold vertical line$ એ $bold rightwards arrow for bold A of bold times bold rightwards arrow for bold B of$ કરતાં 73 % વધારે છે, તો $bold rightwards arrow for bold A of$ અને $bold rightwards arrow for bold B of$ વચ્ચેનો ખુણો ....

30 $degree$
60 $degree$
90 $degree$
0 $degree$

8. $bold vertical line bold space bold rightwards arrow for bold A of bold space bold cross times bold space bold rightwards arrow for bold B of bold vertical line to the power of bold 2 bold space bold plus bold space bold vertical line bold space bold rightwards arrow for bold A of bold times bold rightwards arrow for bold B of bold vertical line to the power of bold 2 bold space bold equals bold space bold. bold. bold. bold. bold. bold. bold. bold. bold. bold space bold. bold space$

A²B²
AB
$square root of AB$
શૂન્ય

9. $bold rightwards arrow for bold A of bold space bold equals bold space bold 3 bold i with bold overbrace on top bold space bold plus bold space bold 4 bold j with bold overparenthesis on top bold space bold minus bold space bold 2 bold k with bold overparenthesis on top bold space$ અને $bold rightwards arrow for bold B of bold space bold equals bold space bold 8 bold i with bold overbrace on top bold space bold plus bold space bold 3 bold i with bold overbrace on top bold space bold plus bold space bold 6 bold k with bold overbrace on top$ વચ્ચે ખુણો .....

60 $degree$
0 $degree$
$90 degree$
$180 degree$

10. m દળના એક પદાર્થ પર ત્રિ પારિમાણિક અવકાશમાં $bold rightwards arrow for bold F of bold space bold equals bold space bold 5 bold space bold i with bold overbrace on top bold space bold minus bold space bold 4 bold i with bold overbrace on top bold space bold plus bold space bold 2 bold k with bold overbrace on top bold space bold N$ બળ લાગે છે, તો આ બળ x-અક્ષ સાથે ......... ખૂણો બનાવશે.

$Cos to the power of negative 1 end exponent space open parentheses 3 square root of 5 close parentheses$
$Cos to the power of negative 1 end exponent space open parentheses fraction numerator square root of 5 over denominator 3 end fraction close parentheses$
$Cos to the power of negative 1 end exponent space open parentheses fraction numerator 1 over denominator 3 square root of 5 end fraction close parentheses$
$Cos to the power of negative 1 end exponent space open parentheses fraction numerator 3 over denominator square root of 5 end fraction close parentheses$

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Gujarati JEE Physics : કાયનેમેટિક્સ

Multiple Choice Questions

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