Book Store

Download books and chapters from book store.
Currently only available for
CBSE Gujarat Board Haryana Board

Previous Year Papers

Download the PDF Question Papers Free for off line practice and view the Solutions online.
Currently only available for
Class 10 Class 12

કિરણ પ્રકાશશાસ્ત્ર

હવામાં એક પાતળા લેન્સનો ઑપ્તિકલ પાવર -5 D છે. તેનો ઑપ્ટિકલ પાવર 1.6 વક્રીભવનાંકવાળા પ્રવાહી માધ્યમમાં કેટલો થશે ?

-25 D
25 D
1 D
0.625 D

0.625 D

Tips: -

bold P bold space bold equals bold space bold 1 over bold f bold space bold equals bold space fraction numerator open parentheses bold n subscript bold 2 bold space bold minus bold space bold n subscript bold 1 close parentheses over denominator bold n subscript bold 1 end fraction bold space open parentheses bold 1 over bold R subscript bold 1 bold space bold minus bold space bold 1 over bold R subscript bold 2 close parentheses

R₁ અને R₂ અચળ હોવાથી

$bold P subscript bold a over bold P subscript bold m bold space bold equals bold space fraction numerator open parentheses begin display style fraction numerator bold n subscript bold g bold space bold minus bold space bold n subscript bold a over denominator bold n subscript bold a end fraction end style close parentheses over denominator open parentheses begin display style fraction numerator bold n subscript bold g bold space bold minus bold space bold n subscript bold m over denominator bold n subscript bold m end fraction end style close parentheses end fraction bold space bold equals bold space fraction numerator open parentheses begin display style fraction numerator bold 1 bold. bold 5 bold space bold minus bold space bold 1 over denominator bold 1 end fraction end style close parentheses over denominator open parentheses begin display style fraction numerator bold 1 bold. bold 5 bold space bold minus bold space bold 1 bold. bold 6 over denominator bold 1 bold. bold 6 end fraction end style close parentheses end fraction bold space bold equals bold space bold minus fraction numerator bold 0 bold. bold 5 over denominator bold 0 bold. bold 1 end fraction bold space bold cross times bold space bold 1 bold. bold 6 bold space bold space bold equals bold space bold minus bold 8 bold therefore bold space bold P subscript bold m bold space bold equals bold space bold minus bold P subscript bold a over bold 8 bold space bold equals bold space bold minus fraction numerator open parentheses bold minus bold 5 close parentheses over denominator bold 8 end fraction bold space bold equals bold space bold 5 over bold 8 bold space bold equals bold space bold 0 bold. bold 625 bold space bold D$