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Class 10 Class 12

સમીકરણ

નીચેનું સમીકરણ ઉકેલો :
$fraction numerator bold 2 bold x over denominator bold 3 end fraction bold space bold plus bold space bold 1 bold space bold equals bold space fraction numerator bold 7 bold x over denominator bold 15 end fraction bold space bold plus bold space bold 3$

નીચેનું સમીકરણ ઉકેલો :
$bold 5 bold x bold space bold plus bold space bold 7 over bold 2 bold space bold equals bold space fraction numerator bold 3 bold x over denominator bold 2 end fraction bold space bold minus bold space bold 14$

bold therefore bold space bold 5 bold x bold space bold minus bold space fraction numerator bold 3 bold x over denominator bold 2 end fraction bold space bold equals bold space bold minus bold 14 bold space bold minus bold space bold 7 over bold 2 bold therefore bold space bold 2 bold space open parentheses bold 5 bold x bold space bold minus bold space fraction numerator bold 3 bold x over denominator bold 2 end fraction close parentheses bold space bold equals bold space bold 2 bold space open parentheses bold minus bold 14 bold space bold minus bold space bold 7 over bold 2 close parentheses bold space bold left parenthesis bold બ ં ન ે bold space bold બ ા જ ુ bold space bold 2 bold space bold વડ ે bold space bold ગ ુ ણત ાં bold right parenthesis bold therefore bold space bold 10 bold x bold space bold minus bold space bold 3 bold x bold space bold equals bold space bold minus bold 28 bold space bold minus bold 7 bold space bold therefore bold space bold 7 bold x bold space bold equals bold space bold minus bold 35 bold therefore bold space bold x bold space bold equals bold space fraction numerator bold minus bold 35 over denominator bold 7 end fraction bold therefore bold space bold x bold space bold equals bold space open parentheses bold minus bold 5 close parentheses

નીચેનું સમીકરણ ઉકેલો :
$bold x over bold 2 bold space bold minus bold space bold 2 bold space bold equals bold space bold x over bold 3 bold space bold plus bold space bold 1$

નીચેનું સમીકરણ ઉકેલો :
$bold x bold space bold equals bold space bold 4 over bold 5 bold space open parentheses bold x bold space bold plus bold space bold 10 close parentheses$

નીચેનું સમીકરણ ઉકેલો :
3x + 8 = -5x + 4

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