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101.

A monkey of mass 30 kg climbs on a massless rope whose breaking strength is 450 N. The rope will break if the monkey (Take g = 10 m/s^{2} )

climbs up with a uniform speed of 5 m/s

climbs down with an acceleration 4 m/s

^{2}climbs up with an acceleration 6 m/s

^{2}climbs down with a uniform speed of 5 m/s

^{2}

102.

A body is at rest at x = 0 and t = 0, it starts moving in the positive X-direction with a constant acceleration. At the same instant, another body passes through x = O moving in the positive X-direction with a constant speed. The position of the first body is given by x_{1} (t) after time t and that of second body by x_{2} (t) after the same time interval. Which of the following graphs correctly describes (x_{1 }_{− }x_{2}) as a function of time t ?

103.

The given graph shows the variation of velocity with displacement. Which one of the graphs given below correctly represents the variation of acceleration with displacement.

104.

In figure shown below, a particle is travelling counter clockwise in circle of radius 10 m. The acceleration vector indicated at a specific time. Find the value of 'v' at this time.

10 m/s

15 m/s

20 m/s

7 m/s

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105.

A ball which is at rest is dropped from a height h metre. As it bounces off the floor its speed is 80% of what it was just before touching the ground. The ball will then rise to nearly a height

0.94 h

0.80 h

0.75 h

0.64 h

106.

Two bodies of different masses are dropped from heights of 16 m and 25 m respectively. The ratio ofthe time taken by them to reach the ground is

$\frac{25}{16}$

$\frac{5}{4}$

$\frac{4}{5}$

$\frac{16}{25}$

107.

A man of height h walks in a straight path towards a lamp post of height H with uniform velocity u. Then the velocity of the edge of the shadow on the ground will be

$\frac{\mathrm{hu}}{\left(\mathrm{H}-\mathrm{h}\right)}$

$\frac{\mathrm{Hu}}{\left(\mathrm{H}+\mathrm{h}\right)}$

$\frac{\left(\mathrm{H}-\mathrm{h}\right)}{\mathrm{Hu}}$

$\frac{\left(\mathrm{H}+\mathrm{h}\right)}{\mathrm{Hu}}$

108.

A train of 150 m length is going towards north direction at a speed of 10 ms^{-1} . A parrot flies at a ,speed of 5ms^{-1} towards south direction parallel to the railway track. The time taken by the parrot to cross the train is equal to

12 s

8 s

15 s

10 s

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109.

The area under acceleration-time graph gives

distance travelled

change in acceleration

force acting

change in velocity

110.

The distance travelled by an object along a straight line in time t is given by s= 3 − 4t + 5t^{2}, the initial velocity of the object is

3 unit

− 3 unit

4 unit

− 4 unit

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