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 Multiple Choice QuestionsMultiple Choice Questions

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31.

What will be the number of waves formed by a Bohr electron in one complete revolution in its second orbit?

  • Three

  • Two

  • One

  • Zero


32.

Match the particle with its characteristic

Column I Column II
A. α-particle p. Slow moving
B. Isobar q. High penetration power
C. γ- ray r. Same atomic mass
D. β- particle s. consists of electron

  • A - p; B - r; C - q; D - s

  • A - p; B - q; C - r; D - s

  • A - r; B - s; C - p; D - q

  • A - s; B - r; C - p; D - q


33.

Highest energy will be absorbed to eject out the electron in the configuration.

  • 1s22s22p1

  • 1s22s22p3

  • 1s22s22p2

  • 1s22s22p4


34.

If n = 6, the correct sequence for filling of electrons will be

  • ns (n - 1)d (n - 2)f np

  • ns (n - 2)f np (n - 1)d

  • ns np (n - 1)d (n - 2)f

  • ns (n - 2)f (n - 1)d np


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35.

An electron is moving in Bohr's fourth orbit. Its de-Broglie wave length is λ. What is the circumference of the fourth orbit?

  • 2λ

  • 2λ

  • 4λ 

  • 4λ


36.

The Vividh Bharti Station of All India Radio, Delhi, broadcasts on a frequency of 1,368 kHz (Kilohertz). Calculate the wavelength (λ) of the electromagnetic radiation emitted by transmitter. Which part of the electromagnetic spectrum does it belong to?

  • 319.4 m and X-rays

  • 319.4 m and radiowave

  • 219.3 m and microwave

  • 219.3 m and radiowave


37.

In an atom, an electron is moving with a speed of 600 m/s with an accuracy of 0.005%. Certainty with which the position of the electron can be located is

(Given, h= 6.6 x 10-34 kg m2 s-1, mass of electron em = 9.1 x 10-31 kg)

  • 215 x 10-3 m

  • 2.78 x 10-3 m

  • 1.92 x 10-3 m

  • 3.24 x 10-3 m


38.

Maximum number of electrons in a subshell of an atom determined by the following?

  • 4l + 2

  • 2n2

  • 4l - 2

  • 2l + 1


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39.

Which one of the following sets of quantum numbers represents the highest energy level in an atom?

  • n = 4; l = 0; m = 0; s = +12

  • n = 3; l = 1; m = 1; s = +12

  • n = 3; l = 2; m = -2; s = +12

  • n = 3; l = 0; m = 0; s = +12


40.

The ratio of the difference in energy between the first and the second Bohr orbit to that between the second and the third Bohr orbit is

  • 12

  • 13

  • 49

  • 275


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