The pressure and density of a diatomic gas change adiabatically from (P1 , ρ1) to (P2 , ρ2) . If , then should be
16
32
64
128
One mole of an ideal gas at an initial temperature of T K does 6R joules of work adiabatically. If the ratio of specific heats of this gas at constant pressure and at constant volume is 5/3, then final temperature of the gas will be
(T − 4) K
(T + 4) K
(T − 2.4)K
(T + 2.4) K
According to first law of thermodynamics
energy is conserved
mass is conserved
heat is constant in isothermal process
heat neither enters nor leaves system
Ten moles of an ideal gas at constant temperature 500 K is compressed from 50 L to 5 L. Work done in the process is (Given, R = 8.31 J-mol-1 - K-1 )
- 1.2 x 104 J
- 2.4 x 104 J
- 4.8 x 104 J
- 9.6 x 104 J
An ideal gas is compressed isothermally until its pressure is doubled and then allowed to expand adiabatically to regain its original volume (γ = 1.4 and 2-1.4 = 0.38). The ratio of the final to initial pressure is
0.76 : 1
1 : 1
0.66 : 1
0.86 : 1
The molar specific heats of an ideal gas at constant pressure and volume are denoted by CP and CV respectively. If and R is the universal gas constant, then CV is equal to
γR
During an adiabatic process, the pressure of a gas is found to be proportional to the cube of its temperature. The ratio of for the gas is
2
A scientist proposes a new temperature scale in which the ice point is 25 X (X is the new unit of temperature) and the steam point is 305 X. The specific heat capacity of water in this new scale is (in J kg-1X-1)
4.2 × 103
3.0 × 103
1.2 × 103
1.5 × 103
One mole of a van der Waals' gas obeying the equation
undergoes the quasi-static cyclic process which is shown in the p-V diagram. The net heat absorbed by the gas in this process is
A heating element of resistance r is fitted inside an adiabatic cylinder which carries a frictionless piston of mass m and cross-section A as shown in diagram. The cylinder contains one mole of an ideal diatomic gas. The piston current flows through the element such that the temperatures rises with time t as ΔT = αt + βt2 ? (α and β are constants), while pressure remains constant. The atmospheric pressure above the piston is P0. Then
he rate of increase in internal energy is
the current flowing in the element is
the piston moves upwards with constant acceleration
the piston moves upwards with constant speed