Subject

Mathematics

Class

CBSE Class 10

Pre Boards

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Sample Papers

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 Multiple Choice QuestionsShort Answer Type

11.

In Fig. , O is the centre of a circle such that diameter AB = 13 cm and AC = 12 cm. BC is joined. Find the area of the shaded region. (Take π = 3.14)

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12.

In Fig., a tent is in the shape of a cylinder surmounted by a conical top of the same diameter. If the height and diameter of cylindrical part are 2.1 m and 3 m respectively and the slant height of conical part is 2.8 m, find the cost of canvas needed to make the tent if the canvas is available at the rate of Rs. 500/sq. metre. (use π = 22/7)

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13.

If the point P(x, y) is equidistant from the points A(a + b, b – a) and B(a – b,a + b). Prove that bx = ay.

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14.

In Fig.  find the area of the shaded region, enclosed between two concentric circles of radii 7 cm and 14 cm where ∠AOC = 40°. (use π =22/7)

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15.

If the ratio of the sum of first n terms of two A.P’s is (7n +1): (4n + 27), find the ratio of their mth terms.

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16.

Solve for x:
fraction numerator 1 over denominator left parenthesis straight x minus 1 right parenthesis left parenthesis straight x minus 2 right parenthesis end fraction plus fraction numerator 1 over denominator left parenthesis straight x minus 2 right parenthesis left parenthesis straight x minus 3 right parenthesis end fraction space equals 2 over 3 comma space straight x not equal to 1 comma 2 comma 3

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17.

A conical vessel, with base radius 5 cm and height 24 cm, is full of water. This water is emptied into a cylindrical vessel of base radius 10 cm. Find the height to which the water will rise in the cylindrical vessel. (π = 22/7)

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18.

A sphere of diameter 12 cm, is dropped in a right circular cylindrical vessel, partly filled with water. If the sphere is completely submerged in water, the water level in the cylindrical vessel rises by 3 5 over 9 cm. Find the diameter of the cylindrical vessel.

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19.

A man standing on the deck of a ship, which is 10 m above water level, observes the angle of elevation of the top of a hill as 60° and the angle of depression of the base of a hill as 30°. Find the distance of the hill from the ship and the height of the hill.




Let CD be the hill and suppose the man is standing on the deck of a ship at point A.

The angle of depression of the base C of the hill CD observed from A is 30° and the angle of elevation of the top D of the hill CD observed from A is 60°.
therefore angle EAD space equals space 60 degree space and space angle BCA space equals 30 degree
In space increment AED comma
tan space 60 degree space equals DE over EA
therefore square root of 3 space equals straight h over straight x
therefore space straight h equals square root of 3 straight x space space... space left parenthesis 1 right parenthesis
In space increment ABC comma
tan space 30 degree space equals space AB over BC
therefore space fraction numerator 1 over denominator square root of 3 end fraction equals 10 over straight x
therefore space straight x equals 10 square root of 3 space in space equation space left parenthesis 1 right parenthesis comma space we space get
straight h equals square root of 3 space straight x 10 square root of 3 space equals space 10 straight x 3 space equals 30
therefore space DE space equals space 30 space straight m
therefore space CD equals CE plus ED space equals 10 plus 30 space equals space 40 space straight m
Thus comma space the space distance space of space the space hill space from space the space ship space is space 10 square root of 3 space straight m space and space
the space height space of space the space hill space is space 40 space straight m.
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20.

Three different coins are tossed together. Find the probability of getting
(i) exactly two heads
(ii) at least two heads
(iii) at least two tails.

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