A moving boat is observed from the top of a 150 m high cliff mov

Subject

Mathematics

Class

CBSE Class 10

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Sample Papers

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 Multiple Choice QuestionsShort Answer Type

11.

Find the sum of n terms of the series open parentheses 4 minus 1 over straight n close parentheses space plus open parentheses 4 minus 2 over straight n close parentheses space plus open parentheses 4 minus 3 over straight n close parentheses space plus.........

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12.

If the equation (1 + m2) x2 + 2mcx + c2 – a2 = 0 has equal roots then show that c2 = a2 (1 + m2). 

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13.

The 3/4th part of a conical vessel of internal radius 5 cm and height 24 cm is full of water. The water is emptied into a cylindrical vessel with internal radius 10 cm. Find the height of water in a cylindrical vessel. 

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14.

In the given figure, OACB is a quadrant of a circle with centre O and radius 3.5 cm. If OD = 2 cm, find the area of the shaded region.

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15.

Two tangents TP and TQ are drawn to a circle with centre O from an external point T. Prove that ∠PTQ = 2 ∠OPQ.

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16.

Show that ΔABC, where A(–2, 0), B(2, 0), C(0, 2) and ΔPQR where P(–4, 0), Q(4, 0), R(0, 2) are similar triangles. 

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17.

The area of a triangle is 5 sq units. Two of its vertices are (2, 1) and (3, –2). If the third vertex is (7/2, y), find the value of y.

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18.

Two different dice are thrown together. Find the probability that the numbers obtained
(i) have a sum less than 7
(ii) have a product less than 16
(iii) is a doublet of odd numbers.

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19.

A moving boat is observed from the top of a 150 m high cliff moving away from the cliff. The angle of depression of the boat changes from 60° to 45° in 2 minutes. Find the speed of the boat in m/h.


Let the distance BC be x m and CD be y m. 



In ∆ABC,
tan space 60 degree space equals space AB over BC space equals space 150 over straight x
rightwards double arrow space square root of 3 space equals space 150 over straight x
rightwards double arrow space straight x space equals space fraction numerator 150 space straight m over denominator square root of 3 end fraction.... space left parenthesis straight i right parenthesis

In ABD,
tan space 45 degree space equals space AB over BD space equals space fraction numerator 150 over denominator straight x plus straight y end fraction
rightwards double arrow space 1 space equals space fraction numerator 150 over denominator straight x plus straight y end fraction
rightwards double arrow straight x space plus straight y space equals space 150
rightwards double arrow space straight y space equals space 150 minus straight x

Using (1), we get
rightwards double arrow space straight y space equals space 150 space minus fraction numerator 150 over denominator square root of 3 end fraction space equals space fraction numerator 150 left parenthesis square root of 3 minus 1 right parenthesis over denominator square root of 3 end fraction space straight m
Time taken to move from point C to point D is 2 min = 2/60 h=1/30 h.
Now,
Speed space equals space Distance over Time space equals space fraction numerator straight y over denominator 1 divided by 30 end fraction
space equals space fraction numerator begin display style fraction numerator 150 left parenthesis square root of 3 minus 1 right parenthesis end root over denominator square root of 3 end fraction end style over denominator 1 divided by 30 end fraction space equals space 1500 square root of 3 left parenthesis square root of 3 minus 1 right parenthesis straight m divided by straight h
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 Multiple Choice QuestionsLong Answer Type

20.

If the mth term of an A. P. is 1 over straight n and nth term is 1 over straight m then show that its (mn)th term is 1. 

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