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CBSE Class 10 Science Solved Question Paper 2011

Short Answer Type

31.

Explain how equal genetic contribution of male and female parents is ensured in the progeny.

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32.

Out of HCl and CH₃COOH, which one is a weak acid and why? Describe an activity to support your answer.

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33.

Two elements X and Y belong to group 1 and 2 respectively in the same period of the periodic table. Compare them with respect to:

(i) the number of valences electrons in their atoms

(ii) their valencies

(iii) metallic character

(iv) the sizes of their atoms

(v) the formulae of their oxides

(vi) the formulae of their chlorides

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34.

Draw the ray diagram and also state the position, the relative size and the nature of image formed by a concave mirror when the object is placed at the centre of curvature of the mirror.

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35.

(i) “The refractive index of diamond is 2.42”. What is the meaning of this statement?

(ii) Name a liquid whose mass density is less than that of water but it is optically denser than water.

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36.

What eye defect is hypermetropia? Describe with a ray diagram how this defect of vision can be corrected by using an appropriate lens.

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37.

(a) List two sexually transmitted disease in each of the following cases:

(i) Bacterial infections

(ii) Viral infections

(b) How may the spread of such diseases be prevented?

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38.

Explain Mendel’s law of independent inheritance. Give one example.

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Long Answer Type

39.
(a) If the image formed by a lens is diminished in size and erect, for all positions of the object, what type of lens is it?

(b) Name the point on the lens through which a ray of light passes undeviated.

(c) An object is placed perpendicular to the principal axis of a convex lens of focal length 20 cm. The distance of the object from the lens is 30 cm. Find (i) the position (ii) the magnification and (iii) the nature of the image formed.

(a) If the image formed by a lens is diminished in size and erect, for all positions of the object, then the lens is a concave lens.

(b) The point on the lens through which a ray of light passes undeviating is known as Pole.

Object distance, u = -30 cm

Focal length, f =20 cm

i) Now, using the len’s formula,

$1 over straight f space equals 1 over straight v minus 1 over straight u 1 over straight v equals 1 over straight f plus 1 over straight u straight v equals fraction numerator straight u space xf over denominator straight u plus straight f end fraction straight v equals fraction numerator left parenthesis negative 30 right parenthesis straight x 20 over denominator 20 minus 30 end fraction straight v equals space 60 space cm The space image space is space formed space at space straight a space distance space of space 60 cm space of space the space other space side space of space the space optical space centre. ii right parenthesis space Magnification comma space straight m equals straight m equals space minus straight v over straight u space equals negative fraction numerator 60 over denominator negative 30 end fraction space equals 2$

(iii) Image formed is inverted.

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40.

One-half of a convex lens is covered with a black paper. Will such a lens produce an image of the complete object? Support your answer with a ray diagram.

(b) An object 5 cm high is held 25 cm away from a converging lens of focal length 10 cm.

(i) Draw the ray diagram and

(ii) Calculate the position and size of the image formed.

(iii) What is the nature of the image?

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