Subject

Mathematics

Class

CBSE Class 12

Pre Boards

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Sample Papers

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 Multiple Choice QuestionsLong Answer Type

11.

Find all points of discontinuity of f, where f is defined as following:

f ( x ) =  x  + 3 ,   x -3                  - 2x       ,   -3 < x < 3           6x + 2   ,     x  3


12.

Find  dydx,  if  y =  cosxx +  sinx 1x


13.

Prove the following: 

tan-1 x = 12 cos-1  1 - x1 + x ,   x  0, 1 


14.

Prove the following:

cos-1 1213 + sin-1 35 = sin-1 5665


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15.

Let * be a binary operation on Q defined by a * b = 3ab5
Show that * is commutative as well as associative. Also find its identity element, if it exists.


16.

Using elementary row operations, find the inverse of the following matrix:

 2 51 3 


17.

Find the equations of the normals to the curve y = x3 + 2x + 6 which are parallel to the line x + 14y + 4 = 0.


18.

Using properties of determinants show the following:

 b + c 2   ab caab       a + c 2  bcac     bc   a + b 2 = 2abc ( a + b + c )3


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19.

Find the values of x for which f(x) = [x(x - 2)]2 is an increasing function. Also, find the points on the curve where the tangent is parallel to x-axis.


f ( x ) =  x  x - 2 2 = x2  x2 - 4 x + 4  = x4 - 4 x3 + 4 x2f ( x ) =  4 x3 - 12 x2 + 8 xf ( x ) = 4 x  x2 - 3 x + 2           = 4 x  x - 2   x - 1 f ( x ) = 0    x = 0   or  1,  2

So, the tangents to curve f ( x ) is parallel to the x-axis if  x = 0,  x = 1  or  x = 2.

Now points  0, 1  and  2 will divide the number line into 4 disjoint intervals 

 -, 0 ,   0, 1 ,  1, 2 ,  2,  

                  

Now in the intervals  -, 0   and   1, 2   f ( x ) < 0. So thefunction f ( x ) is strictly decreasing in these intervals.f ( x ) > 0  in interval ( 0, 1 )  and  ( 2,  )So the function f ( x ) is strictly increasing  in intervals  ( 0, 1 ) and ( 2,  )Tangent is parallel to x-axis if  dydx = 0

Which gives us  x = 0,  1,  2

Hence,  x = 0,  y = 0

x = 1,  y = 0

x = 2,  y = 0

Required points are ( 0, 0 ),  ( 1, 1 ),  ( 2, 0 ).


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20.

Show that the right circular cylinder, open at the top, and of given surface area and maximum volume is such that its height is equal to the radius of the base.


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