Subject

Mathematics

Class

CBSE Class 12

Pre Boards

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Sample Papers

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 Multiple Choice QuestionsShort Answer Type

21.

The scalar product of the vector straight a with rightwards arrow on top equals space straight i with hat on top plus straight j with hat on top plus straight k with hat on top with a unit vector along the sum of vectors straight b with rightwards arrow on top equals 2 straight i with hat on top plus 4 straight j with hat on top minus 5 straight k with hat on top space space and space straight c with rightwards arrow on top space equals space straight lambda straight i with hat on top plus 2 straight j with hat on top plus 3 straight k with hat on top is equal to one. Find the value of straight lambda and hence find the unit vector along straight b with rightwards arrow on top plus straight c with rightwards arrow on top.

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22. Evaluate colon
integral subscript 0 superscript straight pi fraction numerator 4 straight x space sinx over denominator 1 plus cos squared straight x end fraction dx
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23.

Evaluate:
integral fraction numerator straight x plus 2 over denominator square root of straight x squared plus 5 straight x plus 6 end root end fraction dx

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24.

An experiment succeeds thrice as often as it fails. Find the probability that in the next five trials, there will be at least 3 successes.

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25. If space straight y space equals space Pe to the power of ax plus Qe to the power of bx show that
straight d to the power of 2 straight y end exponent over dx squared minus left parenthesis straight a plus straight b right parenthesis dy over dx plus aby space equals 0
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26. If space straight x equals cost left parenthesis 3 minus 2 cos squared straight t right parenthesis space and space straight y equals sint left parenthesis 3 minus 2 sin squared straight t right parenthesis comma space find space the space value space of space dy over dx at space straight t equals straight pi over 4.
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27.

Find the particular solution of the differential equation log open parentheses dy over dx close parentheses equals 3 straight x plus 4 straight y comma space given space that space straight y space equals space 0 comma space when space straight x equals space 0.


Consider the differential equation,
log open parentheses dy over dx close parentheses equals 3 straight x plus 4 straight y
Taking exponent on both the sides, we have
straight e to the power of log open parentheses dy over dx close parentheses end exponent space equals space straight e to the power of 3 straight x plus 4 straight y end exponent
space rightwards double arrow dy over dx equals straight e to the power of 3 straight x plus 4 straight y end exponent
space rightwards double arrow dy over dx equals straight e to the power of 3 straight x end exponent. straight e to the power of 4 straight y end exponent
rightwards double arrow dy over straight e to the power of 4 straight y end exponent equals straight e to the power of 3 straight x end exponent. dx
Integration in both the sides, we have
integral dy over straight e to the power of 4 straight y end exponent space equals space integral straight e to the power of 3 straight x end exponent dx
fraction numerator straight e to the power of negative 4 straight y end exponent over denominator negative 4 end fraction equals straight e to the power of 3 straight x end exponent over 3 plus straight C
We space need space to space find space the space particular space solution
We space have comma space straight y space equals space 0 comma space when space straight x space equals space 0
fraction numerator 1 over denominator negative 4 end fraction space equals 1 third plus straight C
rightwards double arrow straight C space equals negative 1 fourth minus 1 third
rightwards double arrow straight C space equals space fraction numerator negative 3 minus 4 over denominator 12 end fraction equals negative 7 over 12
Thus comma space the space solution space is space straight e to the power of 3 straight x end exponent over 3 plus straight e to the power of negative 4 straight y end exponent over 4 equals 7 over 12

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28.

Find the value of p, so that the lines:
are perpendicular to each other. Also find the equations of a line passing through a point (3, 2, -4) and parallel to line l1.

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 Multiple Choice QuestionsLong Answer Type

29.

Find the equation of the plane through the line of intersection of the planes x + y + z = 1 and 2x + 3y + 4z = 5 which is perpendicular to the plane x- y + z = 0. Also find the distance of the plane obtained above, from the origin.

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30.

Find the distance of the point (2, 12, 5) from the point of intersection of the line 
straight r with rightwards arrow on top equals 2 straight i with hat on top minus 4 straight j with hat on top plus 2 straight k with hat on top plus straight lambda open parentheses 3 straight i with hat on top plus 4 straight j with hat on top plus 2 straight k with hat on top close parentheses space and space the space plane space straight r with rightwards arrow on top. open parentheses straight i with hat on top minus 2 straight j with hat on top plus straight k with hat on top close parentheses equals 0.

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