Subject

Mathematics

Class

CBSE Class 12

Pre Boards

Practice to excel and get familiar with the paper pattern and the type of questions. Check you answers with answer keys provided.

Sample Papers

Download the PDF Sample Papers Free for off line practice and view the Solutions online.
Advertisement

 Multiple Choice QuestionsShort Answer Type

11.

Show that the four points A(4,5,1), B(0,-1,-1), C(3,9,4) and D(-4,4,4)
are coplanar.

2439 Views

 Multiple Choice QuestionsLong Answer Type

12.

Let A= R × R and * be a binary operation on A defined by

(a, b) * (c, d) = (a+c, b+d)

Show that * is commutative and associative. Find the identity element for *

on A. Also find the inverse of every element (a, b) ∈ A.

1283 Views

13. Prove space that space straight y equals fraction numerator 4 space sin space straight theta over denominator 2 space plus cos space straight theta end fraction space minus straight theta space is space an space increasing space function space of space straight theta space on space open square brackets 0 comma straight pi over 2 close square brackets
1368 Views

Advertisement

14.

Show that semi-vertical angle of a cone of maximum volume and given slant height is cos-1fraction numerator 1 over denominator square root of 3 end fraction.


Volume space of space cone space equals 1 third πr squared straight h
space equals 1 third straight pi left parenthesis space straight l space sin space straight alpha right parenthesis squared space left parenthesis space straight l space space cos space straight alpha right parenthesis
equals 1 third space straight pi space straight l cubed space sin squared space straight alpha space cos space straight alpha
dv over dα equals πl cubed over 3 left square bracket negative sin cubed space straight alpha space plus 2 sin space straight alpha space cosx space. cos space straight alpha right square bracket
equals fraction numerator straight pi space straight l cubed space sin space straight alpha over denominator 3 end fraction left parenthesis negative sin squared space straight alpha space plus space 2 space cos squared space straight alpha right parenthesis
For space maximum space volume


dv over dα space equals 0
fraction numerator πl cubed space sin space straight alpha over denominator 3 end fraction left parenthesis negative s i n space squared space alpha space plus 2 space c o s squared space alpha right parenthesis equals 0
s i n space alpha space not equal to 0
space 2 space c o s squared space alpha space equals space s i n squared space alpha
t a n squared space alpha space equals 2
t a n alpha space equals square root of 2
c o s space alpha space equals space fraction numerator 1 over denominator square root of 3 end fraction
alpha space equals space c o s to the power of negative 1 end exponent fraction numerator 1 over denominator square root of 3 end fraction

again space diff space straight w. straight r. straight t space straight alpha comma space we space get
fraction numerator straight d squared straight v over denominator dα squared end fraction space equals 1 third πl cubed cos squared space straight alpha left parenthesis 2 minus 7 space tan squared space straight alpha right parenthesis
at space cos space straight alpha space equals fraction numerator 1 over denominator square root of 3 end fraction
fraction numerator straight d squared straight v over denominator dα squared end fraction space less than 0
straight V space is space maximum space when space cos space straight alpha space equals fraction numerator 1 over denominator square root of 3 end fraction space or space straight alpha space equals cos to the power of negative 1 end exponent fraction numerator 1 over denominator square root of 3 end fraction
1713 Views

Advertisement
Advertisement
15.

Using properties of determinants, prove that

open vertical bar table row cell left parenthesis straight x plus straight y right parenthesis squared end cell zx zy row zx cell left parenthesis straight z plus straight y right parenthesis squared end cell xy row zy xy cell left parenthesis straight z plus straight x right parenthesis squared end cell end table close vertical bar space space equals space 2 xyz left parenthesis straight x plus straight y plus straight z right parenthesis cubed

1198 Views

16. If space straight A space equals space open square brackets table row 1 0 2 row 0 2 1 row 2 0 3 end table close square brackets space and space straight A cubed minus 6 straight A squared plus 7 straight A space plus kI subscript 3 space equals space 0 space find space straight k.
860 Views

 Multiple Choice QuestionsShort Answer Type

17.

Write the sum of intercepts cut off by the planestraight r with rightwards arrow on top. open parentheses 2 straight i with hat on top plus straight j with hat on top minus straight k with hat on top close parentheses minus 5 space equals 0 on the three axes.

1312 Views

18. find space straight lambda space and space straight mu space if

open parentheses straight i with hat on top plus space 3 space straight j with hat on top space plus space 9 space straight k with hat on top close parentheses space space straight x space space left parenthesis 3 space straight i with hat on top plus straight lambda space straight j with hat on top plus space straight mu space straight k with hat on top right parenthesis space equals space 0
928 Views

Advertisement
19. If space straight a with rightwards arrow on top equals 4 space straight i with hat on top space minus straight j with hat on top plus space straight k with hat on top space and space straight b with rightwards arrow on top space equals space 2 space straight i with hat on top space minus 2 straight j with hat on top plus space straight k with hat on top comma then space find space straight a space vector space parallel space to space the space vector space straight a with rightwards arrow on top plus straight b with rightwards arrow on top.
1199 Views

20. space F i n d space colon integral fraction numerator left parenthesis 2 x minus 5 right parenthesis e to the power of 2 x end exponent over denominator left parenthesis 2 x minus 3 right parenthesis end fraction d x
1136 Views

Advertisement