Subject

Chemistry

Class

ICSE Class 12

Pre Boards

Practice to excel and get familiar with the paper pattern and the type of questions. Check you answers with answer keys provided.

Sample Papers

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 Multiple Choice QuestionsShort Answer Type

11. If the half-life period for a first order reaction is 69.3 seconds, what is the value of its rate constant ?
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12. Define cryoscopic constant.
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13. Ethylene glycol is used as an antifreeze agent. Calculate the amount of ethylene glycol to be added to 4 kg of water of prevent it from freezing at -6°C. (Kfor H20 = 1.85 K mole-1 kg) 
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14. The freezing point of a solution containing 0.3 gms of acetic acid in 30 gms of benzene is lowered by 0.45K. Calculate the Van’t Hoff factor. (at. wt. of C = 12, H = 1, 0 =16, Kf for benzene = 5.12K kg mole-1)
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15.

(b) Name the law or principle confirmed by the following observations :  

(i) When water is added to 0.01M aqueous solution of acetic acid the number of hydrogen ions increase.

(ii) When 96500 coulombs of electricity is passed through acidulated water, 5.6 litres of oxygen at s.t.p. is liberated at the anode.

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16.

Arrange Ag, Cr and Hg metals in the increasing order of reducing power. Given :

E° Ag+/Ag = +0.80V    E° cr+3/cr = -0.74V    E° Hg2/Hg = +0.79V

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17.

In a first order reaction, 10% of the reactant is consumed in 25 minutes. Calculate :

(i) The half-life of the reaction.   

(ii) The time required for completing 17% of the reaction.


straight K equals fraction numerator space 2.303 over denominator straight t end fraction space log space open parentheses fraction numerator straight a over denominator straight a minus straight x end fraction close parentheses space equals fraction numerator space 2.303 over denominator 25 end fraction log space open parentheses fraction numerator 100 over denominator 100 minus 10 end fraction close parentheses space equals space 4.215 space straight x space 10 to the power of negative 3 end exponent space min to the power of negative 1 end exponent

straight i right parenthesis space Half space life space left parenthesis straight t subscript 1 divided by 2 end subscript right parenthesis space equals space fraction numerator 0.693 over denominator straight K end fraction space equals fraction numerator space 0.693 over denominator 4.215 space straight x space 10 to the power of negative 3 end exponent end fraction space equals 164.41 space mintues

ii right parenthesis space straight t equals space fraction numerator 2.303 over denominator straight K end fraction log space open parentheses fraction numerator straight a over denominator straight a minus straight x end fraction close parentheses space equals space fraction numerator 2.303 over denominator 4.215 space straight x space 10 to the power of negative 3 end exponent end fraction log space open parentheses fraction numerator 100 over denominator 100 minus 17 end fraction close parentheses space equals space 44.21 space minutes
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18.

(a) Explain giving reasons why (Give equations in support of your answer):

(i) A solution of NH4Cl and NH4OH acts as a buffer.

(ii) Cu is precipitated as CuS while Zn is not precipitated when H2S is passed through an acidic solution of Cu(NO3)2 and Zn(NO3)2 respectively.

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19.

(i) What is Schottky defect in a solid?

(ii) A bcc element (atomic mass 65) has a cell edge of 420 pm. Calculate its density in gms / cm3.

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20.

(i)Give Lewis’ definition for acids and bases.    

(ii) The solubility of Ag2CrO4 at 25°C is 8.0 x 10-5 moles /litre. Calculate its solubility product.

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