Subject

Chemistry

Class

JEE Class 12

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 Multiple Choice QuestionsMultiple Choice Questions

1.

Chlorine (Cl17) free radical contains how many electrons around the nucleus?

  • 16

  • 17

  • 18

  • 19


2.

4 L- atom is equal to

  • 40.50 cal

  • 78.75 cal

  • 95.23 cal

  • 96 cal


3.

How many gram-equivalents of NaOH are required to neutralise 25 cm3 of a decinormal HCl solution?

  • 0.00125

  • 0.0025

  • 0.0050

  • 0.025


4.

Ammonium acetate which is 0.01 M, is hydrolysed to 0.001 M concentration. Calculate the change in pH in 0.001 M solution, if initially pH = pKa

  • 5

  • 10

  • 100

  • 1


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5.

1 mol alcohol reacts with Na to give what weight of hydrogen ?

  • 1 gm

  • 2 gm

  • 3 gm

  • 3.5 gm


6.

Find the correct equation

  • E2 - E1 - H2 + H1 = n2RT - n1RT

  • E2 - E1 - H2 - H1 = n2RT - n1RT

  • H2 - H1 - E2 + E1 = n2RT - n1RT

  • H2 - H1 - E2 - E1 = n2RT - n1RT


7.

Reaction for the formation of NaCl is

  • Na(g) + Cl2(g) → NaCl(s)

  • Na(s) + 12Cl2(g) → NaCl(s)

  • Na(g) + 12Cl2(g) → NaCl(s)

  • Na(g) + Cl2(g) → NaCl(g)


8.

1 u (amu) is equal to

  • 1.492 × 10-10 J

  • 1.492 × 10-7 J

  • 1.492 × 10-13 J

  • 6.023 × 1023 J


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9.

Which of the ions is colourless inspite of the presence of unpaired electrons ?

  • La3+

  • Eu3+

  • Gd3+

  • Lu3+


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10.

Conjugate acid-base pair differ by

  • electron

  • proton

  • neutron

  • hydroxyl group


B.

proton

According to  acids convert into conjugate base and after gaining a proton, bases convert into their conjugate acid, i.e. 

Acid - H+ → conjugate base

Base - H+ → conjugate acid

Thus, conjugate acid-base pair is differ by proton.


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