Subject

Chemistry

Class

JEE Class 12

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 Multiple Choice QuestionsMultiple Choice Questions

31.

Sodium thiosulphate is used in photography

  • as AgBr grain is reduced to non-metallic silve

  • to convert metallic silver into silver salt

  • to remove reduced silver

  • to remove undecomposed AgBr in the form of Na3[Ag(S2O3)2] (a complex salt)


32.

Ice crystallises in a hexagonal lattice. At the low temperature, the lattice constants were a = 4.53 Å and b = 7.41 Å. How many H2O molecules are contained in a unit cell? [d(ice) =0.92 g /cm3 ]

            

  • 4

  • 3

  • 2

  • 1


33.

A 0.001 molal solution of [Pt(NH3)4Cl4] in water had a freezing point depression of 0.0054°C. If Kf for water is 1.80, the correct formulation of the above molecules is

  • [Pt(NH3)4Cl3]Cl

  • [Pt(NH3)4Cl2]Cl2

  • [Pt(NH3)4Cl]Cl2

  • [Pt(NH3)4Cl4]


34.

If M is molecular weight of solvent, Kb is molal elevation constant, Tb is its boling point p° is its vapour pressure at temperature T and ps is vapour pressure of its solution having a non- volatile solute at T K , then

  • p°-psp°= TbKb×M

  • p°-psp°=KbTb×M

  • p°-psp°=KbTb×M1000

  • p°-psp°=TbKb×M1000


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35.

Which of the following statements is correct for Tyndall effect?

  • Scattering and polarising of light by small suspended particles is called Tyndall effect

  • Tyndall effect of colloidial particles is due to dispersion of light

  • Tyndall effect is due to refraction of light

  • Tyndall effect is zig-zag motion of suspended particles.


36.

Calculate the ionic radius of a Cs+ ion, assuming that the cell edge lenght for CsCl is 0.4123 nm and that the ionic radius of a Cl- ion is 0.181 nm

  • 0.176 nm

  • 0.231 nm

  • 0.357 nm

  • 0.166 nm


37.

The pair of molecules forming strongest hydrogen bonds are

  • HCOOH and CH3COOH

  • CH3COOH and CHCl3

  • H2O and H2

  • SiF6 and SiH4


38.

Which of the following reasonating structures is not correct for


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39.

Which of the following represents the correct order of the acidity in the given compound?

  • ClCH2COOH < BrCH2COOH< CH3COOH < FCH2COOH

  • CH3COOH < BrCH2COOH < ClCH2COOH < FCH2COOH

  • FCH2COOH < ClCH2COOH < BrCH2COOH < CH3COOH

  • CH3COOH < ClCH2COOH < BrCH2COOH < CH3COOH


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40.

What will be the major product when 2-amino propane is treated with nitrous acid?

  • Propane-2-ol

  • Cyclopropene

  • Propanol

  • 2-rntropropane


A.

Propane-2-ol


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