Subject

Chemistry

Class

JEE Class 12

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 Multiple Choice QuestionsMultiple Choice Questions

31.

During nuclear explosion one of the products is 90Sr with half-life of 28.1 yr. If 1 μg of 90Sr was absorbed in the bones of a newly born body instead of calcium, how much of it will remain after 60 yr, if it is not lost metabolically?

  • 0.184 μg

  • 0.025 μg

  • 0.262 μg

  • 0.228 μg


32.

A colloidal system having a solid substance as a dispersed phase and a liquid as a dispersion medium is classified as

  • solid sol

  • gel

  • emulsion

  • sol


33.

In a first order reaction, the concentration of the reactant, decreases from 0.8 M to 0.4 M in 15 min. The time taken for the concentration to change from 0.1 M to 0.025 M is

  • 30 min

  • 15 min

  • 7.5 min

  • 160 min


34.

Calculate the osmotic pressure of 0.01 M solution of cane sugar at 300 K (R = 0.08212 atm degree-1 mol-1)

  • 0.3568 atm

  • 0.2463 atm

  • 0.1562 atm

  • 0.5623 atm


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35.

Given, ECr3+/ Cr° = -0.72 V, EFe2+/ Fe° = -0.42 V. The potential for the cell Cr | Cr3+ (0.1 M) || Fe2+ (0.01 M) | Fe is

  • 0.26 V

  • 0.399 V

  • -0.399 V

  • -0.26 V


A.

0.26 V

Cr | Cr3+ (0.1M) || Fe2+ (0.01 M) | Fe

Oxidation half-cell- Cr → Cr3+ + 3e- × 2

Reduction half-cell- Fe2+ + 2e- → Fe × 3

Net cell reaction,

2Cr + 3Fe2+ → 2Cr3+ + 3Fe, n = 6

Ecell° = Eoxi° + Ered°       = 0.72 - 0.42 = 0.30 V

Ecell = Ecell° - 0.0591n log [Cr3+]2[Fe2+]3         = 0.30 - 0.05916 log (0.1)2(0.01)3         =  0.30  - 0.05916 log 10-210-6         = 0.30 - 0.05916 log 104

Ecell = 0.2606 V


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36.

In a reaction, A + B → C, the rate expression is R = k [A][B]2. If the concentration of both the reactant is doubled at constant volume, then the rate of the reaction will be

  • eight times

  • double

  • quadruple

  • triple


37.

Red lead is

  • PbO

  • Pb3O4

  • PbO2

  • Pb4O3


38.

Which among the following will anisotrophy?

  • glass

  • plastic

  • barium chloride

  • wood


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39.

Concentrated HNO3 forms NO2+ in the presence of

  • Conc. H2SO4

  • Fe

  • FeBr3

  • AlCl3


40.

CH3MgBr + CH2 = CH-COH H3O+ Product

It is (1 : 4 addition)

  • CH2=CH-C||CH3OH-H

  • CH2OH-CH=CH-CH3

  • CH3CH2CH2CHO

  • None of the above


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