Subject

Chemistry

Class

JEE Class 12

Test Series

Take Zigya Full and Sectional Test Series. Time it out for real assessment and get your results instantly.

Test Yourself

Practice and master your preparation for a specific topic or chapter. Check you scores at the end of the test.
Advertisement

 Multiple Choice QuestionsMultiple Choice Questions

21.

The reaction of zinc with dilute and concentrated nitric acid, respectively, produces:

  • NO2 and NO

  • NO and N2O

  • NO2 and N2O

  • NO2 and N2O

519 Views

22.

Galvanization is applying a coating of:

  • Cr

  • Cu

  • Zn

  • Zn

267 Views

23.

2-chloro-2-methylpentane on reaction with sodium methoxide in methanol yields:

  • Both a and c

  • Only c

  • Both a and b

  • Both a and b

1011 Views

24.

Which of the following statements about low-density polythene is false?

  • It is a poor conductor of electricity

  • Its synthesis requires dioxygen or a peroxide initiator as a catalyst.

  • It is used in the manufacture of buckets, dustbins etc.

  • It is used in the manufacture of buckets, dustbins etc.

398 Views

Advertisement
25.

Which of the following is an anionic detergent?

  • Sodium lauryl sulphate

  • Cetyltrimethyl ammonium bromide

  • Glyceryl oleate

  • Glyceryl oleate

389 Views

26.

The absolute configuration of

is:

  • (2S, 3R)

  • (2S, 3S)

  • (2R, 3R)

  • (2R, 3R)

332 Views

27.

Thiol group is present in:

  • Cystine

  • Cysteine

  • Methionine

  • Methionine

353 Views

Advertisement

28.

In the Hofmann bromamide degradation reaction, the number of moles of NaOH and Br2 used per mole of amine produced are:

  • Four moles of NaOH and two moles of Br2

  • Two moles of NaOH and two moles of Br2

  • Four moles of NaOH and one mole of Br2

  • Four moles of NaOH and one mole of Br2


C.

Four moles of NaOH and one mole of Br2

Hofmann-bromamide degradation reaction is given as

RCONH2 + 4 NaOH + Br2 → RNH2 + Na2CO3 + 2NaBr + 2H2O

Hence four moles of NaOH and one mole of Br2 are used.

475 Views

Advertisement
Advertisement
29.

The reaction of propene with HOCl(Cl2+H2O) proceeds through the intermediate:

  • CH3−CH+−CH2−Cl

  • CH3−CH(OH)−C+H2

  • CH3−CHCl−C+H2

  • CH3−CHCl−C+H2

763 Views

30.

The product of the reaction given below is:

314 Views

Advertisement