Subject

Mathematics

Class

JEE Class 12

Test Series

Take Zigya Full and Sectional Test Series. Time it out for real assessment and get your results instantly.

Test Yourself

Practice and master your preparation for a specific topic or chapter. Check you scores at the end of the test.
Advertisement

 Multiple Choice QuestionsMultiple Choice Questions

51.

ABC is a triangle. Forces straight P with rightwards arrow on top comma space straight Q with rightwards arrow on top comma space straight R with rightwards arrow on top space acting along IA, IB and IC respectively are in equilibrium, where I is incentre of ∆ABC. Then P : Q : R is

  • sin A : sin B : sin C

  • sin space straight A over 2 space colon space Sin space straight B over 2 space colon space sin space straight C over 2
  • cos space straight A over 2 colon space cos space straight B over 2 space colon space Cos space straight C over 2
  • cos space straight A over 2 colon space cos space straight B over 2 space colon space Cos space straight C over 2
201 Views

52.

If C is the mid -point of AB and P is any point outside AB, then

  • PA with rightwards arrow on top space plus space PB with rightwards arrow on top space equals space 2 PC with rightwards arrow on top
  • PA with rightwards arrow on top space plus space PB with rightwards arrow on top space equals space PC with rightwards arrow on top
  • PA with rightwards arrow on top space plus space PB with rightwards arrow on top space plus space 2 PC with rightwards arrow on top space equals space 0
  • PA with rightwards arrow on top space plus space PB with rightwards arrow on top space plus space 2 PC with rightwards arrow on top space equals space 0
129 Views

53.

The normal to the curve x = a(cosθ + θ sinθ), y = a( sinθ - θ cosθ) at any point ‘θ’ is such that

  • it passes through the origin

  • it makes angle π/2 + θ with the x-axis

  • it passes through (aπ/2 ,-a)

  • it passes through (aπ/2 ,-a)

141 Views

Advertisement

54.

The area enclosed between the curve y = loge (x + e) and the coordinate axes is

  • 1

  • 2

  • 3

  • 3


A.

1

Required space area space left parenthesis OAB right parenthesis space equals space integral subscript 1 minus straight e end subscript superscript 0 space In space left parenthesis straight x space plus straight e space right parenthesis thin space dx
space equals space open square brackets straight x space ln space left parenthesis straight x plus space straight e right parenthesis minus integral fraction numerator 1 over denominator straight x plus straight e end fraction straight x space dx close square brackets subscript 0 superscript 1 space space equals 1
258 Views

Advertisement
Advertisement
55.

The parabolas y2 = 4x and x2 = 4y divide the square region bounded by the lines x = 4, y = 4 and the coordinate axes. If S1, S2, S3 are respectively the areas of these parts numbered from top to bottom; then S1 : S2: S3 is

  • 1 : 2 : 1

  • 1 : 2 : 3

  • 2 : 1 : 2

  • 2 : 1 : 2

243 Views

56.

The line parallel to the x−axis and passing through the intersection of the lines ax + 2by + 3b = 0 and bx − 2ay − 3a = 0, where (a, b) ≠ (0, 0) is

  • below the x−axis at a distance of 3/2 from it

  • below the x−axis at a distance of 2 /3 from it

  • above the x−axis at a distance of 3/ 2 from it

  • above the x−axis at a distance of 3/ 2 from it

121 Views

57. integral space open curly brackets fraction numerator left parenthesis log space straight x minus 1 right parenthesis over denominator 1 plus left parenthesis log space straight x right parenthesis squared end fraction close curly brackets squared space dx space is space equal space to
  • fraction numerator log space straight x over denominator left parenthesis log space straight x right parenthesis squared plus 1 end fraction plus space straight C
  • fraction numerator straight x over denominator straight x plus 1 end fraction space plus straight C
  • fraction numerator xe to the power of straight x over denominator 1 plus straight x squared end fraction plus straight C
  • fraction numerator xe to the power of straight x over denominator 1 plus straight x squared end fraction plus straight C
103 Views

58.

Let f : R → R be a differentiable function having f (2) = 6, f′ (2) =(1/48) . Then limit as straight x space rightwards arrow 2 of space integral subscript 6 superscript straight f left parenthesis straight x right parenthesis end superscript space fraction numerator 4 straight t cubed over denominator straight x minus 2 end fraction dt space equals

  • 24

  • 36

  • 12

  • 12

108 Views

Advertisement
59.

Let f (x) be a non−negative continuous function such that the area bounded by the curve y = f (x), x−axis and the ordinates x = π/4  and x = β >  π/4 open parentheses straight beta space sin space straight beta space plus space straight pi over 4 space cos space straight beta space plus space square root of 2 straight beta close parentheses. Then f (π/2) is

  • open parentheses straight pi over 4 plus square root of 2 minus 1 close parentheses
  • open parentheses straight pi over 4 minus square root of 2 plus 1 close parentheses
  • open parentheses 1 minus straight pi over 4 minus square root of 2 plus 1 close parentheses
  • open parentheses 1 minus straight pi over 4 minus square root of 2 plus 1 close parentheses
117 Views

60.

If the angle θ between the line fraction numerator straight x plus 1 over denominator 1 end fraction space equals space fraction numerator straight y minus 1 over denominator 2 end fraction space equals space fraction numerator straight z minus 2 over denominator 2 end fractionand the plane space 2 straight x minus space straight y plus space square root of straight lambda space straight z space plus 4 space equals 0 is such of sin θ = 1/3 the value of λ is

  • 5/3

  • -3/5

  • 3/4

  • 3/4

105 Views

Advertisement