Subject

Mathematics

Class

JEE Class 12

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 Multiple Choice QuestionsMultiple Choice Questions

21.

There are two urns. Urn A has 3 distinct red balls and urn B has 9 distinct blue balls. From each urn two balls are taken out at random and then transferred to the other. The number of ways in which this can be done is

  • 3

  • 36

  • 66

  • 66

150 Views

22.

The area bounded by the curve y = cos x and y = sin x between the ordinates x = 0 and x = 3π/2 is 

  • left parenthesis 4 minus square root of 2 minus 2 right parenthesis space sq space units
  • left parenthesis 4 minus square root of 2 plus 2 right parenthesis space sq space units
  • left parenthesis 4 minus square root of 2 minus 1 right parenthesis space sq space units
  • left parenthesis 4 minus square root of 2 minus 1 right parenthesis space sq space units
444 Views

23.

Solution of the differential equation
cos x dy = y (sin x - y) dx, 0 < x < π/2, is 

  • sec x = (tan x + C ) y 

  •  y sec x = tan x + C

  •  y tan x = sec x + C 

  •  y tan x = sec x + C 

243 Views

24.

A line AB in three-dimensional space makes angles 45° and 120° with the positive x-axis and the positive y-axis respectively. If AB makes an acute angle θ with the positive z-axis, then θ

  • 30°

  • 45°

  • 60°

  • 60°

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25.

The circle x2+ y2 = 4x + 8y + 5 intersects the line 3x – 4y = m at two distinct points if

  • -85 < m < -35

  • -35 < m < 15

  • 15 < m < 65

  • 15 < m < 65

247 Views

26.

An urn contains nine balls of which three are red, four are blue and two are green. Three balls are drawn at random without replacement from the urn. The probability that the three balls have different colours is

  • 1/3

  • 2/7

  • 1/21

  • 1/21

115 Views

27.

Let bold a bold space bold equals bold j with bold hat on top bold minus bold k with bold hat on top bold space and bold c bold space bold equals bold space bold i with bold hat on top bold minus bold j with bold hat on top bold minus bold k with bold hat on top. Then, the vector b satisfying a x b + c = 0  and a.b  = 3

  • negative straight i with hat on top plus straight j with hat on top space minus 2 straight k with hat on top
  • 2 straight i with hat on top minus straight j with hat on top space plus 2 straight k with hat on top
  • negative straight i with hat on top minus straight j with hat on top space minus 2 straight k with hat on top
  • negative straight i with hat on top minus straight j with hat on top space minus 2 straight k with hat on top
162 Views

28.

If the vectors bold a bold space bold equals bold space bold i with bold hat on top bold space bold minus bold j with bold hat on top bold space bold plus bold 2 bold k with bold hat on top bold comma bold space bold b bold space bold equals bold 2 bold i with bold hat on top bold space bold plus bold 4 bold j with bold hat on top bold space bold plus bold k with bold hat on top bold space bold and bold space bold c bold space bold equals bold space bold lambda bold i with bold hat on top bold space bold plus bold j with bold hat on top bold space bold plus bold mu bold k with bold hat on top are mutually orthogonal, then (λ,μ) is equal to

  • (-3,2)

  • (2,-3)

  • (-2,3)

  • (-2,3)

129 Views

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29.

The line L given by straight x over 5 space plus straight y over straight b space equals space 1 passes through the point (13, 32). The line K is parallel to L and has the equation straight x over straight c space plus straight y over 3 space equals space 1 . Then the distance
between L and K is

  • fraction numerator 23 over denominator square root of 15 end fraction
  • square root of 17
  • fraction numerator 17 over denominator square root of 15 end fraction
  • fraction numerator 17 over denominator square root of 15 end fraction


D.

fraction numerator 17 over denominator square root of 15 end fraction

Since, the line L is passing through the point (13,32)
Therefore,

13 over 5 space plus 32 over straight b space equals space 1
rightwards double arrow space 32 over straight b space equals space minus 8 over 5
rightwards double arrow space straight b space equals space minus 20
The line K is parallel to the line L then its equation must be

straight x over 5 minus straight y over 20 space equals straight a space
Or
fraction numerator straight x over denominator 5 straight a end fraction minus fraction numerator straight y over denominator 20 straight a end fraction space equals space 1
On space comparing space with space straight x over straight c space plus straight y over 3 space equals space 1 comma space we space straight g space et
20 straight a space equals space minus space 3 comma space straight c space equals 5 straight a space equals space minus 3 over 4
Hence comma space the space distance space between space lines
fraction numerator vertical line straight a minus 1 vertical line over denominator square root of begin display style 1 over 25 plus 1 over 400 end style end root end fraction space equals space fraction numerator open vertical bar begin display style fraction numerator negative 3 over denominator 20 end fraction minus 1 end style close vertical bar over denominator square root of begin display style 17 over 400 end style end root end fraction space equals space fraction numerator 23 over denominator square root of 17 end fraction

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30.

Four numbers are chosen at random (without replacement) from the set {1, 2, 3, ..., 20}.

Statement-1: The probability that the chosen numbers when arranged in some order will form an AP is 1 85.
Statement-2: If the four chosen numbers form an AP, then the set of all possible values of common difference is {±1, ±2, ±3, ±4, ±5}.

  • Statement-1 is true, Statement-2 is true; Statement-2 is a correct explanation for Statement-1.

  • Statement-1 is true, Statement-2 is true; statement-2 is not a correct explanation for Statement-1.

  • Statement-1 is true, Statement-2 is false.

  • Statement-1 is true, Statement-2 is false.

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