Subject

Mathematics

Class

JEE Class 12

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 Multiple Choice QuestionsMultiple Choice Questions

11.

A straight line through the point A (3, 4) is such that its intercept between the axes is bisected at A. Its equation is

  • 3x - 4y + 7 = 0

  • 4x + 3y = 24

  • 3x + 4y = 25

  • x + y = 7


12.

The tangent at (1, 7) to the curve x2 = y - 6 touches the circle x2 + y2 + 16x + 12y + c = 0 at

  • (6, 7)

  • (- 6, 7)

  • (6, - 7)

  • (- 6, - 7)


13.

The equation of straight line through the intersection of the lines x - 2y = 1 and x + 3y = 2 and parallel to 3x + 4y = 0 is

  • 3x + 4y + 5 = 0

  • 3x + 4y - 10 = 0

  • 3x + 4y - 5 = 0

  • 3x + 4y + 6 = 0


14.

The eccentricity of the ellipse, which meets the straight line x7 + y2 = 1 on the axis of x and the staraight line x3 - y5 = 1 on the axis of y and whose axes lie along the axes of coordinate, is

  • 327

  • 267

  • 37

  • None of the above


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15.

If x2a2 + y2b2 = 1 a > b and x2 - y2 = c2 cut at right angles, then

  • a2 + b2 = 2c2

  • b2 - a2 = 2c2

  • a2 - b2 = 2c2

  • a2b2 = 2c2


C.

a2 - b2 = 2c2

Given, x2a2 + y2b2 = 1         ...(i)On differentiating w.r.t. x, we get   2xa2 + 2yb2 . dydx = 0 dydx = - xb2a2y and x2 - y2 = c2On differentiating w.r.t. x, we get2x - 2ydydx = 0        dydx = xy

The two curves will cut at right angles, ifdydxc1 × dydxc2 = - 1     - b2xa2y . xy = - 1                 x2a2 = y2b2      x2a2 = y2b2 = 1             using Eq. (i)

On substituting these values in x2 - y2 = c2, we get

  a22 - b22 = c2 a2 - b2 = 2c2


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16.

The equation of the conic with focus at (1, - 1) directrix along x - y + 1 = 0 and with eccentricity 2, is

  • x2 - y2 = 1

  • xy = 1

  • 2xy - 4x + 4y + 1 = 0

  • 2xy + 4x - 4y - 1 = 0


17.

There are 5 letters and 5 different envelopes. The number of ways in which all the letters can be put in wrong envelope, is

  • 119

  • 44

  • 59

  • 40


18.

The sum of the series

1 + 12 + 222! + 12 + 22 + 323! + 12 + 22 + 32 + 424! + ... is

  • 3e

  • 176e

  • 136e

  • 196e


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19.

The coefficient of xn in the expansion of loga1 + x is

  • - 1n - 1n

  • - 1n - 1nlogae

  • - 1n - 1nlogea

  • - 1nnlogae


20.

The value of limxπ2 - tan-1x1x is

  • 0

  • 1

  • - 1

  • e


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