Subject

Mathematics

Class

JEE Class 12

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 Multiple Choice QuestionsMultiple Choice Questions

11.

The part of circle x2 + y2 = 9 in between y = 0 and y = 2 is revolved about y-axis. The volume of generating solid will be

  • 463π

  • 12π

  • 16π

  • None of these


12.

The solution of the differential equation xdy - ydx = x2 + y2dx is

  • y - x2 + y2 = Cx2

  • y + x2 + y2 = Cx2

  • y + x2 + y2 + Cx2 = 0

  • None of the above


13.

The solution of dydx = cosx2 - ycscx where y = 2, when x = π2 is

  • y = sinx + cscx

  • y = tanx2 + cotx2

  • y = 12secx2 + 2cosx2

  • None of the above


14.

The solution of the equation sin-1dydx = x + y is

  • tanx + y + secx + y = x + C

  • tanx + y - secx + y = x + C

  • tanx + y - secx + y + x + C = 0

  • None of the above


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15.

The angle between two diagonals of a cube will be

  • sin-113

  • cos-113

  • variable

  • None of these


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16.

The lines x - a + dα - δ = y - aα = z - a - dα + δ and x - b + cβ - τ = y - bβ = z - b - cβ + τ are coplanar and then equation to the plane in which they lie, is

  • x + y + z = 0

  • x - y + z = 0

  • x - 2y + z = 0

  • x + y - 2z = 0


C.

x - 2y + z = 0

The lines will be coplanar, if

a - d - b + ca - ba + d - b - cα - δαα + δβ - τββ + τ = 0

Add 3rd columnto first and it becomes twice the second and hence the determinant is zero, as the two columns are identical. Again, the equation ofthe plane in which they lie is

x - a + dy - az - a - dα - δαα + δβ - τββ + τ = 0

On adding 1st and 3rd columns and subtracting twice the 2nd, we get

x + z - 2yy - az - a - d0αα + δ0ββ + τ = 0

 αβ + τ - βα + δx +z - 2y = 0                                     x +z - 2y = 0


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17.

If 0t2x fxdx = 25t5,t > 0, then f425 is

  • 25

  • 52

  • - 25

  • None of these


18.

Three forces of magnitudes 1, 2 and 3 dynes meet in a point and act along diagonals of three adjacent faces of a cube. The resultant force is

  • 114 dynes

  • 6 dynes

  • 5 dynes

  • None of the above


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19.

The vectors AB = 3i + 5j + 4k and AC = 5i - 5j + 2k are side of a ABC. The length ofthe median through A is

  • 13 units

  • 25 units

  • 5 units

  • 10 units


20.

Let a = 2i + j + k, b = i + 2j - 1, and a unit vector c be caplanar. If c is perpendicular to a, then c is

  • 12- j  + k

  • 13- i - j - k

  • 15i - 2j

  • 13i - j  - k


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