Subject

Mathematics

Class

JEE Class 12

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 Multiple Choice QuestionsMultiple Choice Questions

11.

Let a,b,c and d be non-zero numbers. If the point of intersection of the lines 4ax +2ay +c= 0 and 5bx +2by +d = 0 lies in the fourth quadrant and is equidistant from the two axes, then

  • 2bc-3ad =0 

  • 2bc+3ad =0

  • 2ad-3bc =0

  • 2ad-3bc =0

252 Views

12.

The locus of the foot of perpendicular drawn from the centre of the ellipse x2+3y2 =6 on any tangent to it is

  • (x2-y2)2 = 6x2+2y2

  • (x2-y2)2 = 6x2 -2y2

  • (x2+y2)2 = 6x2+2y2

  • (x2+y2)2 = 6x2+2y2

659 Views

13.

Let C be the circle with centre at(1,1) and radius 1. If T is the circle centred at (0,y) passing through origin and touching the circle externally, then the radius of T is equal to

  • fraction numerator square root of 3 over denominator square root of 2 end fraction
  • fraction numerator square root of 3 over denominator 2 end fraction
  • 1/2

  • 1/2

395 Views

14.

The slope of the line touching both the parabolas y2 = 4x and x2-32y is 

  • 1/2

  • 3/2

  • 1/8

  • 1/8

398 Views

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15.

The image of line fraction numerator straight x minus 1 over denominator 3 end fraction space equals space fraction numerator straight y minus 3 over denominator 1 end fraction space equals space fraction numerator straight z minus 4 over denominator negative 5 end fraction in the plane 2x-y+z+3 =0 is the line

  • fraction numerator straight x plus 3 over denominator 3 end fraction space equals space fraction numerator straight y minus 5 over denominator 1 end fraction space equals space fraction numerator straight z minus 2 over denominator negative 5 end fraction
  • fraction numerator straight x plus over denominator negative 3 end fraction space equals space fraction numerator straight y minus 5 over denominator negative 1 end fraction space equals space fraction numerator begin display style straight z plus 2 end style over denominator 5 end fraction
  • fraction numerator straight x minus 3 over denominator 3 end fraction space equals space fraction numerator straight y plus 5 over denominator 1 end fraction space equals space fraction numerator straight z minus 2 over denominator negative 5 end fraction
  • fraction numerator straight x minus 3 over denominator 3 end fraction space equals space fraction numerator straight y plus 5 over denominator 1 end fraction space equals space fraction numerator straight z minus 2 over denominator negative 5 end fraction
382 Views

16.

The statement ~ (p↔ ~q) is 

  • equivalent to p ↔ q

  • equivalent to ~ p ↔q

  • a tautology

  • a tautology

184 Views

17.

A bird is sitting on the top of a vertical pole 20m high and its elevation from a point O n the ground is 45o. It flies off horizontally straight away from the point O. After 1s, the elevation of the bird from O is reduced to 30o. Then, the speed (in m/s of the bird is

  • (40 square root of 2 minus end root space 1

  • 40 left parenthesis square root of 3 space space end root space minus space square root of 2 right parenthesis
  • 20 space square root of 2
  • 20 space square root of 2
211 Views

18.

The variance of first 50 even natural number is

  • 833/4

  • 833

  • 437

  • 437

177 Views

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19.

If [a x b b x c c x a] = λ[a b c]2, then λ is equal to 

  • 0

  • 1

  • 2

  • 2

261 Views

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20.

If α, β ≠ 0 and f(n) = αn+ βn and 

open vertical bar table row 3 cell 1 plus straight f left parenthesis 1 right parenthesis space space space space end cell cell 1 plus space straight f left parenthesis 2 right parenthesis end cell row cell 1 plus straight f left parenthesis 1 right parenthesis space space space space space end cell cell 1 plus straight f left parenthesis 2 right parenthesis space space space space space space end cell cell 1 plus straight f left parenthesis 3 right parenthesis end cell row cell 1 plus straight f left parenthesis 2 right parenthesis space space space end cell cell 1 plus straight f left parenthesis 3 right parenthesis space space space space space space space end cell cell 1 plus space straight f left parenthesis 4 right parenthesis end cell end table close vertical bar
= K(1-α)2(1-β)2(α- β)2, then K is equal to 

  • αβ 

  • 1/αβ 

  • 1

  • 1


C.

1

f(n) = αn + βn
f(1) = α + β
f(2) = α2 + β2 
f(3) =α3 + β3
f(4) = α4 + β4


Let Δ = open vertical bar table row 3 cell 1 plus straight f left parenthesis 1 right parenthesis space space space space end cell cell 1 plus space straight f left parenthesis 2 right parenthesis end cell row cell 1 plus straight f left parenthesis 1 right parenthesis space space space space space end cell cell 1 plus straight f left parenthesis 2 right parenthesis space space space space space space end cell cell 1 plus straight f left parenthesis 3 right parenthesis end cell row cell 1 plus straight f left parenthesis 2 right parenthesis space space space end cell cell 1 plus straight f left parenthesis 3 right parenthesis space space space space space space space end cell cell 1 plus space straight f left parenthesis 4 right parenthesis end cell end table close vertical bar

open vertical bar table row 3 cell 1 plus straight alpha space plus space straight beta space space space space end cell cell 1 plus space straight alpha squared space plus space straight beta squared space end cell row cell 1 plus straight alpha space plus space straight beta space space space space space end cell cell 1 plus straight alpha squared space plus space straight beta squared space space space space space space space end cell cell 1 plus straight alpha cubed space plus space straight beta cubed space end cell row cell 1 plus straight alpha squared space plus space straight beta squared space space end cell cell 1 plus straight alpha cubed space plus space straight beta cubed space space space space space space space space end cell cell 1 plus straight alpha to the power of 4 space plus space straight beta to the power of 4 space end cell end table close vertical bar
equals space open vertical bar table row cell 1.1 plus 1.1 plus 1.1 end cell cell 1.1 plus 1. straight alpha space plus 1 space. straight beta space space space space end cell cell 1 plus space 1. straight alpha squared space plus space 1. straight beta squared space end cell row cell 1.1 plus 1. straight alpha space plus 1. space straight beta space space space space space end cell cell 1.1 plus straight alpha. straight alpha space plus space straight beta. straight beta space space space space space space space end cell cell 1 plus straight alpha. straight alpha squared space plus space. ββ squared end cell row cell 1.1 plus 1. straight alpha squared space plus space 1. space straight beta squared space space end cell cell 1 plus straight alpha squared. straight alpha space plus space straight beta squared. straight beta space space space space space space space space end cell cell 1 plus straight alpha squared straight alpha squared space plus space straight beta squared. straight beta squared space end cell end table close vertical bar

equals space open vertical bar table row 1 1 1 row 1 straight alpha straight beta row 1 cell straight alpha squared end cell cell straight beta squared end cell end table close vertical bar open vertical bar table row 1 1 1 row 1 straight alpha straight beta row 1 cell straight alpha squared end cell cell straight beta squared end cell end table close vertical bar space equals space open vertical bar table row 1 1 1 row 1 straight alpha straight beta row 1 cell straight alpha squared end cell cell straight beta squared end cell end table close vertical bar squared
On expanding, we get
Δ = (1- α2 + (1-β2 )(α-β)2
Δ =  K(1-α)2(1-β)2(α- β)2
K=1
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