Subject

Mathematics

Class

JEE Class 12

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 Multiple Choice QuestionsMultiple Choice Questions

31.

The area in the first quadrant between x2 + y2π2 and y = sin(x) is


32.

The area bounded by y = xelxl and lines lxl = 1, y = 0 is,

  • 4 sq units

  • 6 sq units

  • 1 sq unit

  • 2 sq unit


33.

The solution of dydx = x2 + y2 + 12xy, satisfying y(1) = 0 is given by

  • hyperbola

  • circle

  • ellipse

  • parabola


34.

If x . dydx + y = x . fxyf'xy, then f(xy) is equal to

  • k . ex22

  • k . ey22

  • k . ex2

  • k . exy2


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35.

The differential equation of the rectangular hyperbola, where axes are the asymptotes of the hyperbola, is

  • ydudx = x

  • xdydx = - y

  • xdydx = y

  • xdy + ydx = c


36.

The length of longer diagonal of the parallelogram constructed on 5a + 2b and a - 3b, if it is given that a = 22, b = 3and the angle between a and b is π4, is

  • 15

  • 113

  • 593

  • 369


37.

If r = αb × c + βc × a + γa × b and [a b c] = 2, then α + β + γ is equal to

  • r . b × c + c × a + a × b

  • 12r . a +b + c

  • 2r . (a + b + c)

  • 4


38.

If a, b, c are three non-coplanar vectors and p, q, rare reciprocal vectors, then (la + mb + nc) · (lp + mq + nr) is equal to

  • l + m + n

  • l3 + m3 + n3

  • l2 + m2 + n2

  • None of these


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39.

If the integers m and n are chosen at random from 1 to 100, then the probability that a number of the form 7n + 7m is divisible by 5, equals to

  • 14

  • 12

  • 18

  • 13


A.

14

Let l = 7n + 7m, then we observe that 71, 72, 7and 74 ends in 7, 9, 3 and 1, respectively. Thus, tends in 7, 9, 3 or 1 according as i is of the form 4K + 1, 4K + 2, 4K - 1 or 4K, respectively.

If S is the sample space, then n(S) = (100)2. 7m + 7n is divisible by 5, if

(i) m is of the form 4K + 1 and n is of the form 4K - 1 or

(ii) m is of the form 4K + 2 and n is of the form 4K or

(iii) m is of the form 4K - 1 and n is of the form 4K + 1 or

(iv) m is of the form 4K and n is of the form 4K + 1.

Thus, number of favourable ordered pairs (m, n) = 4 × 25 × 25.

Hence, required probability = 4 × 25 × 251002 = 14


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40.

Let X denote the sum of the numbers obtained when two fair dice are rolled. The variance and standard deviation of X are

  • 316 and 316

  • 356 and 356

  • 176 and 176

  • 316 and 356


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