Subject

Physics

Class

JEE Class 12

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 Multiple Choice QuestionsMultiple Choice Questions

21.

One solid sphere A and another hollow sphere B are of same mass and same outer radii. Their moment of inertia about their diameters are respectively IA and IB such that


Where dA and dB are their densities.

  • IA = IB

  • IA > IB

  • IA < IB

  • IA < IB

415 Views

22.

What would be the work done in stretching a wire.

    143 Views

    23.

    Spherical balls of radius R are falling in a viscous fluid of viscosity η with a velocity v. The retarding viscous force acting on the spherical ball is

    • directly proportional to R but inversely proportional to v.

    • directly proportional to both radius R and velocity v.

    • inversely proportional to both radius R and velocity v.

    • inversely proportional to both radius R and velocity v.

    709 Views

    24.

    If two soap bubbles of different radii are connected by a tube,

    • air flows from the bigger bubble to the smaller bubble till the sizes are interchanged.

    • air flows from bigger bubble to the smaller bubble till the sizes are interchanged

    • air flows from the smaller bubble to the bigger.

    • air flows from the smaller bubble to the bigger.

    253 Views

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    25.

    The bob of a simple pendulum executes simple harmonic motion in water with a period t, while the period of oscillation of the bob is t0 in the air. Neglecting frictional force of water and given that the density of the bob is (4/3) x 1000 ms-1 . What relationship between t and t0 is true?

    • t = t0

    • t = t0/2

    • t = 2t0

    • t = 2t0

    3326 Views

    26.

    A particle at the end of a spring executes simple harmonic motion with a period t1, while the corresponding period for another spring is t2. If the period of oscillation with the two springs in series is t, then

    • T = t1 + t2

    • straight T squared space equals space straight t subscript 1 superscript 2 space plus space straight t subscript 2 superscript 2
    • space straight T to the power of negative 1 end exponent space equals straight t subscript 1 superscript negative 1 end superscript space plus straight t subscript 2 superscript negative 1 end superscript
    • space straight T to the power of negative 1 end exponent space equals straight t subscript 1 superscript negative 1 end superscript space plus straight t subscript 2 superscript negative 1 end superscript
    1552 Views

    27.

    The total energy of particle, executing simple harmonic motion is

    • ∝ x

    • ∝ x2

    • independent of x

    • independent of x

    404 Views

    28.

    The displacement y of a particle in a medium can be expressed as y = 10−6 sin(110t + 20 x + π/4) m, where t is in seconds and x in a meter. The speed of the wave is

    • 2000 m/s

    • 5 m/s

    • 20 m/s

    • 20 m/s

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    29.

    A particle of mass m is attached to a spring (of spring constant k) and has a natural angular frequency ω0. An external force F(t) proportional to cosωt (ω≠ω0) is applied to the oscillator. The time displacement of the oscillator will be proportional to

    • fraction numerator straight m over denominator straight omega subscript 0 superscript 2 minus straight omega squared end fraction
    • fraction numerator 1 over denominator straight m left parenthesis straight omega subscript 0 superscript 2 minus straight omega squared right parenthesis end fraction
    • fraction numerator 1 over denominator straight m left parenthesis straight omega subscript 0 superscript 2 plus straight omega squared right parenthesis end fraction
    • fraction numerator 1 over denominator straight m left parenthesis straight omega subscript 0 superscript 2 plus straight omega squared right parenthesis end fraction
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    30.

    In forced oscillation of a particle the amplitude is maximum for a frequency ω1 of the force, while the energy is maximum for a frequency ω2 of the force, then

    • ω1 = ω2

    • ω1 > ω2

    • ω1 < ω2 when damping is small and ω1 > ω2 when damping is large

    • ω1 < ω2 when damping is small and ω1 > ω2 when damping is large


    A.

    ω1 = ω2

    For amplitude of oscillation and energy to be maximum, frequency of force must be equal to the initial frequency and this is only possible in case of resonance. In resonance state ω1 = ω2

    651 Views

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