Test Series

Take Zigya Full and Sectional Test Series. Time it out for real assessment and get your results instantly.

Test Yourself

Practice and master your preparation for a specific topic or chapter. Check you scores at the end of the test.

JEE Physics Solved Question Paper 2013

Multiple Choice Questions

61.

The angle of incidence for an equilateral prism of refractive index $\sqrt{3}$ so that the ray is parallel to the base inside the prism is

30°
20°
60°
45°

62.

If the intensity ratio of two coherent sources used in Young's double slit experiment is 49 : 1, then the ratio between the maximum and minimum intensities in the interference pattern is

1 : 9
9 : 16
16 : 9
16 : 25

63.

According to Rayleigh scattering law, the amount of scattering is

directly proportional to wavelength of light
directly proportional to square of wavelength of light
inversely proportional to fourth power of wavelength of light
inversely proportional to wavelength of light

64.

The de-Broglie wavelength and kinetic energy of a particle is 2000 $\overset{\circ}{A}$ and 1 eV respectively. If its kinetic energy becomes 1 MeV, then its de-Broglie wavelength is

$2 \overset{\circ}{A}$
$1 \overset{\circ}{A}$
$4 \overset{\circ}{A}$
$10 \overset{\circ}{A}$

65.

The work functions of two metals are 2.75 eV respectively. If these are irradiated by photons of energy 3 eV, the ratio of maximum momenta of the photoelectrons emitted respectively by them is

1 : 2
1 : 3
1 : 4
2 : 1

66.

A radioactive material of half-life time of 69.3 days kept in a container. $\frac{2}{3} rd$ of the substance remains undecayed after (given, $\ln \frac{3}{2} = 0.4$ )

20 days
25 days
35 days
40 days

67.

The maximum kinetic energy of photoelectrons

depends on collector plate
is independent of emitter plate material
is independent of frequency of incident radiation
depends on the frequency of light source and the nature of emitter plate material

68.

Identify the mismatched pair from the following

Zener diode : Voltage regulator
Germanium doped with phosphorus : n-type semiconductor
semiconductor : band gap > 3 eV
p-n junction diode : rectifier

69.
In a common-emitter configuration, a transistor has β = 50 and input resistance 1 kΩ. If the peak value of AC input is 0.01 V, then the peak value of collector current is

0.01 µA

500 µA

100 µA

0.5 µA

500 µA

Given, β = 50, V = 0.01 V and R = 1 kΩ = 1000 Ω

Here, $β = \frac{i_{c}}{i_{b}}$

$\frac{i_{c}}{i_{b}} = 50 {(i_{b})}_{\max} = \frac{0.01}{1000} = 1 \times 10^{- 5} A {(i_{c})}_{\max} = {(i_{b})}_{\max} \times β {(i_{c})}_{\max} = (1 \times 10^{- 5}) \times 50 {(i_{c})}_{\max} = 500 μA$