In an experiment for determination of refractive index of glass

Subject

Physics

Class

JEE Class 12

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 Multiple Choice QuestionsMultiple Choice Questions

21.

An observer looks at a distant tree of height 10 m with a telescope of magnifying power of 20. To the observer the tree appears:

  • 10 times taller.

  • 10 times nearer.

  • 20 times taller.

  • 20 times taller.

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22.

The box of a pinhole camera, of length L, has a hole of radius a. It is assumed that when the hole is illuminated by a parallel beam of light of wavelength λ the spread of the spot (obtained on the opposite wall of the camera) is the sum of its geometrical spread and the spread due to diffraction. The spot would then have its minimum size (say bmin) when:

  • straight a equals space straight lambda squared over straight L space and space straight b subscript min space equals space open parentheses fraction numerator 2 straight lambda squared over denominator straight L end fraction close parentheses
  • straight a space equals space square root of λL space and space straight b subscript min space equals open parentheses fraction numerator 2 straight lambda squared over denominator straight L end fraction close parentheses
  • straight a space equals space square root of λL space and space straight b subscript min space equals square root of space open parentheses 4 λL close parentheses end root
  • straight a space equals space square root of λL space and space straight b subscript min space equals square root of space open parentheses 4 λL close parentheses end root
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23.

Radiation of wavelength λ is incident on a photocell. The fastest emitted electron has to speed v. If the wavelength is changed to 3λ/4, the speed of the fastest emitted electron will be:

  • less than straight v space open parentheses 4 over 3 close parentheses to the power of 1 divided by 2 end exponent
  •  = v(4/3)1/2

  •  = v(4/3)1/2

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24.

Half-lives of two radioactive elements A and B are 20 minutes and 40 minutes, respectively. Initially, the samples have equal number of nuclei. After 80 minutes, the ratio of decayed numbers of A and B nuclei will be:

  • 1: 16

  • 4 : 1

  • 1: 4

  • 1: 4

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25.

If a, b, c, d are inputs to a gate and x is its output, then, as per the following time graph, the gate is:


  • NOT

  • AND

  • OR

  • OR

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26.

Choose the correct statement:

  • In amplitude modulation, the amplitude of the high-frequency carrier wave is made to vary in proportion to the amplitude of the audio signal.

  • In amplitude modulation, the frequency of the high-frequency carrier wave is made to vary in proportion to the amplitude of the audio signal.

  • In frequency modulation, the amplitude of the high-frequency carrier wave is made to vary in proportion to the amplitude of the audio signal.

  • In frequency modulation, the amplitude of the high-frequency carrier wave is made to vary in proportion to the amplitude of the audio signal.

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27.

A pipe open at both ends has a fundamental frequency f in the air. The pipe is dipped vertically in water so that half of it is in water. The fundamental frequency of the air column is now:

  • f/2

  • 3f/4

  • 2f

  • 2f

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28.

In an experiment for determination of refractive index of glass of a prism by i− δ, plot, it was found that a ray incident at angle 35o, suffers a deviation of 408 and that it emerges at angle 79o ⋅ Ιn that case which of the following is closest to the maximum possible value of the refractive index?

  • 1.5

  • 1.6

  • 1.7

  • 1.7


A.

1.5

C.

1.7

If μ is the refractive index of the material of prism, the from shell's law

straight mu space equals space fraction numerator sin space straight i over denominator sin space straight r end fraction space equals space fraction numerator sin space left parenthesis straight A space plus straight delta subscript straight m right parenthesis divided by 2 over denominator sin space straight A divided by 2 end fraction space space left parenthesis straight i right parenthesis
Where space straight A space is space angle space of space prism space and space straight delta subscript straight m space is space minimum space deviation space through space prism
Given comma space straight i space equals space 35 to the power of straight o comma space straight delta space equals space 40 to the power of straight o comma space straight e space equals space 79 to the power of straight o
so comma space angle space of space deviation space by space straight a space glass space prism comma
straight delta space equals space straight i space plus space straight e minus space straight A
40 to the power of straight o space equals space 35 to the power of straight o space plus 79 to the power of straight o minus space straight A
straight i. straight e space angle space of space prism space rightwards double arrow space straight A space equals space 74 to the power of straight o
So space angle space of space deviation space by space straight a space glass space prism
straight delta space equals space straight i space plus space straight e minus straight A
rightwards double arrow space 40 to the power of straight o space equals space 35 to the power of straight o space plus 79 to the power of straight o minus space straight A
straight i. straight e space angle space of space prism space rightwards double arrow space straight A space equals space 74 to the power of straight o
let space us space put space straight mu space equals space 15 space in space eq space left parenthesis straight i right parenthesis space we space get
1.5 space equals space fraction numerator sin open parentheses begin display style fraction numerator straight A space plus straight delta subscript min over denominator 2 end fraction end style close parentheses over denominator Sin space straight A divided by 2 end fraction
1.5 space equals space fraction numerator sin open parentheses begin display style fraction numerator 74 to the power of straight o space plus straight delta subscript min over denominator 2 end fraction end style close parentheses over denominator Sin 37 to the power of straight o end fraction
0.9 space equals space sin space open parentheses 37 to the power of o space plus delta subscript m i n end subscript over 2 close parentheses left parenthesis therefore space sin space 37 to the power of straight o space equals space 0.6 right parenthesis
sin space 64 to the power of straight o space equals space sin space open parentheses 37 to the power of straight o space plus straight delta subscript min over 2 close parentheses space left parenthesis therefore space sin space 64 to the power of straight o space equals space 0.9 right parenthesis
37 to the power of o space plus delta subscript m i n end subscript over 2 space equals space 64 to the power of straight o space rightwards double arrow straight delta subscript min space equals space 54 to the power of straight o space
This angle is greater than the 40o and deviation angle already given. For greaterμ deviation will be even higher. Hence μ of the given prism should be lesser than 1.5. Hence, the closest option will be 1.5

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29.

Identify the semiconductor devices whose characteristics are given below, in the order (a), (b), (c), (d):

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