If hydrogen electrode dipped in two-solution of pH = 3 and pH = 6 and salt bridge is connected , the emf of resulting cell is :
0.177 V
0.3 V
0.052 V
0.104 V
A.
0.177 V
[H+] of first solution = 10-pH = 10-3
[H+] of second solution = 10-6
We know ,
= - 0.059 log
= - 0.059 log 10-3
= - 0.059 x - 3 log 10
= - 0.059 x - 3 X 1
= + 0.177 V