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NEET Chemistry Solved Question Paper 2006

Multiple Choice Questions

The radius of hydrogen atom is 0.53 Å. The radius of ₃Li²⁺ is of:

1.27 Å
0.17 Å
0.57 Å
0.99 Å

0.17 Å

The radius of hydrogen atom = 0.53 Å.

₃Li⁺² ion consists of only 1 electron but it has 3 protons in its nucleus. Hence, its electron fall is three times more attracted from nucleus as compared to hydrogen atom. Thus, the radius of ₃Li⁺² is = $\frac{0.53}{3}$ = 0.17 Å

Which one of the following pair shows Buffer's solution?

NaCl + NaOH
CH₃COONa + CH₃COOH
CH₃COOH + CH₃COONH₄
H₂SO₄ + CuSO₄

CH₃COONa + CH₃COOH

Buffer's solutions are the solutions which resists the chnages in its pH value on addition of small amount of a base or an acid.

Among all the given options, CH₃COOH and CH₃COONa are the example of Buffer's solutions because they are the combination of weak acid and salt of strong base.

Which is correct for an enothermic reaction?

$∆$ H is positive
$∆$ H is negative
$∆$ E is negative
$∆$ H= zero

$∆$ H is positive

For an endothermic reactions $∆ H$ is positive because in endothermic reaction heat is always absorbed.

The correct sequence of hybridisation of methane, ethene and acetylene is :

sp, sp², sp³
sp², sp³, sp
sp³, sp², sp
sp³, sp, sp²

sp³, sp², sp

The correct sequence of hybridisation of methane, ethene and ethyne is sp³, sp² and sp.

By dissolving 5 g substance in 50 g of water, the decrease in freezing point is 1.2°C. The gram molal depression is 1.85°C. The molecular weight of substance is :

105.4
118.2
137.2
154.2

154.2

We know,

m = $\frac{1000 K_{f} \times w}{∆ TW}$

Here, $∆ T$ = 1.2°C; K_f = 1.85°

w = 5 gm; W = 50 gm

$∴$ m = $\frac{1000 \times 1.85 \times 5}{1.2 \times 50}$ = 154.2

154.2 is the molecular weight of a substance.

35.4 ml of HCl is required for the neutralization of a solution containing 0.275 g of sodium hydroxide. The normality of hydrochloric acid is ?

0.97 N
0.142 N
0.194 N
0.244 N

0.194 N

We know,

1 gm equivalent weight of NaOH = 40 gm

$∴$ 40 gm of NaOH = 1 gm eq. of NaOH

$∴$ 0.275 gm of NaOH = $\frac{1}{40}$ × 0.275

= $\frac{1}{40}$ × 0.274 × 1000

= 6.88 m eq.

$∴$ $\underset{(HCl)}{N_{1} V_{1}} = \underset{(NaOH)}{N_{2} V_{2}}$

N₁ × 35.4 = 6.88 ( $∵$ meq = NV)

$N_{1} = 0.194$

Which of the following chloride is water insoluble?

HCl
AgCl
Both 'a' and 'b'
None of these

AgCl

AgCl is insoluble in water because the forces favouring the formation of silver hydroxide are too weak to break the ionic bonds between silver and chlorine.